Menu Close

Category: Integration

prove-that-1-2-e-4x-6-12x-5-15x-4-10x-3-4x-2-x-dx-e-1-8-3-1-6-1-2-2-2-1-3-1F2-1-3-2-3-1-6-1-69-2-5-6-128-4-1-3-1F2-4-3-5

Question Number 99120 by  M±th+et+s last updated on 18/Jun/20 provethat:12e(4x6+12x5+15x4+10x3+4x2+x)dx$$=\frac{\sqrt[{\mathrm{8}}]{{e}}}{\mathrm{3}}\left[\frac{\Gamma\left(\frac{\mathrm{1}}{\mathrm{6}}\right)^{\frac{−\mathrm{1}}{\mathrm{2}}} }{\mathrm{2}\sqrt[{\mathrm{3}}]{\mathrm{2}}}\mathrm{1}{F}\mathrm{2}\left(_{\mathrm{1}/\mathrm{3},\mathrm{2}/\mathrm{3}} ^{\mathrm{1}/\mathrm{6}} \mid\frac{−\mathrm{1}}{\mathrm{69}/\mathrm{2}}\:\right)\:+\frac{\Gamma\left(\mathrm{5}/\mathrm{6}\right)}{\mathrm{128}\sqrt[{\mathrm{3}}]{\mathrm{4}}}\mathrm{1}{F}\mathrm{2}\left(_{\mathrm{4}/\mathrm{3},\mathrm{5}/\mathrm{3}}…

A-n-2-2017-1-n-2tan-1-x-sin-1-2x-1-x-2-dx-B-n-2-2017-1-n-2tan-1-x-sin-1-2x-1-x-2-dx-A-B-

Question Number 33570 by Joel578 last updated on 19/Apr/18 A=2017n=2[n12tan1x+sin1(2x1+x2)dx]$${B}\:=\:\underset{{n}=\mathrm{2}} {\overset{\mathrm{2017}} {\prod}}\:\left[\underset{\mathrm{1}} {\overset{{n}} {\int}}\:\mathrm{2tan}^{−\mathrm{1}} \:{x}\:+\:\mathrm{sin}^{−\mathrm{1}} \left(\frac{\mathrm{2}{x}}{\mathrm{1}\:+\:{x}^{\mathrm{2}}…