Question Number 32627 by Cheyboy last updated on 29/Mar/18 $${plzz}\:{help}\:{ne}\:{differentiate}\: \\ $$$${between} \\ $$$$\int{sin}\left(\mathrm{2}{x}\right)=\:−\frac{\mathrm{1}}{\mathrm{2}}{cox}\left(\mathrm{2}{x}\right)+{c}\: \\ $$$${is}\:{not}\:{change}\:{to}\:\int\mathrm{2}{sin}\left({x}\right){cos}\left({x}\right) \\ $$$${but}\:\underset{{b}} {\overset{{a}} {\int}}{sin}\left(\mathrm{2}{x}\right)=\:{is}\:{change}\:{to} \\ $$$$\underset{{b}} {\overset{{a}} {\int}}\mathrm{2}{sin}\left({x}\right){cos}\left({x}\right) \\…
Question Number 163688 by mnjuly1970 last updated on 09/Jan/22 Answered by Lordose last updated on 13/Jan/22 Answered by Lordose last updated on 13/Jan/22 Terms of…
Question Number 98151 by M±th+et+s last updated on 11/Jun/20 $$\int{e}^{{x}^{\mathrm{5}} +\mathrm{8}{x}^{\mathrm{2}} } {dx} \\ $$$$=\frac{\sqrt{\pi}}{\mathrm{4}\sqrt{\mathrm{2}}}{e}^{{x}^{\mathrm{5}} } {erfi}\left(\mathrm{2}\sqrt{\mathrm{2}}{x}\right)−\frac{\mathrm{5}\sqrt{\pi}}{\mathrm{4}\left(\mathrm{128}\right)\sqrt{\mathrm{2}}}\left({super}−{erf}_{\left({hyper}\right)} \left(\mathrm{2}\sqrt{\mathrm{2}}{x}\right)\right)+{c} \\ $$$$ \\ $$$${where}\left[{super}−{erf}_{\left({hyper}\right)} \left({t}\right)\right]\:{is}\:{super}−{function} \\ $$$${in}\:{D}_{\mathrm{2}}…
Question Number 98105 by mathmax by abdo last updated on 11/Jun/20 $$\mathrm{calculate}\:\int_{\mathrm{3}} ^{+\infty} \:\:\:\frac{\left(\mathrm{x}+\mathrm{1}\right)\mathrm{dx}}{\left(\mathrm{x}−\mathrm{2}\right)^{\mathrm{2}} \left(\:\mathrm{2x}+\mathrm{3}\right)^{\mathrm{3}} } \\ $$ Answered by MJS last updated on 11/Jun/20…
Question Number 163619 by Zaynal last updated on 08/Jan/22 $$\boldsymbol{{Prove}}\:\boldsymbol{{that}}; \\ $$$$\:\:\int_{−\infty} ^{\mathrm{0}} \:\boldsymbol{{e}}^{−\mid\boldsymbol{{t}}\mid} \:\boldsymbol{{dt}}\:=\:\mathrm{1} \\ $$ Commented by alephzero last updated on 08/Jan/22 $$\int_{−\infty}…
Question Number 163614 by rajol last updated on 08/Jan/22 $$\int\frac{{sec}^{\mathrm{2}} {x}}{\left({secx}+{tanx}\right)^{\mathrm{9}/\mathrm{2}} }{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 163577 by bobhans last updated on 08/Jan/22 $$\:\:\:\int_{−\mathrm{1}} ^{\:\mathrm{1}} \left(\frac{\mathrm{1}}{\mathrm{1}−\mathrm{ax}}\right)\mathrm{ln}\:\left(\frac{\mathrm{1}+\mathrm{x}}{\mathrm{1}−\mathrm{x}}\right)\:\mathrm{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 163573 by Zaynal last updated on 08/Jan/22 Commented by MJS_new last updated on 08/Jan/22 $$=\frac{\mathrm{sec}^{−\mathrm{1}} }{\mathrm{3cosec}^{−\mathrm{1}} }\int\frac{{dx}}{{x}^{\mathrm{2}} } \\ $$$$\mathrm{or}\:\mathrm{rewrite}\:\mathrm{it}\:\mathrm{properly} \\ $$ Terms…
Question Number 163574 by Zaynal last updated on 08/Jan/22 $$\boldsymbol{{Show}}\:\boldsymbol{{that}}; \\ $$$$\:\:\:\:\:\:\:\:\:\int_{\mathrm{1}} ^{\infty} \:\frac{\boldsymbol{{In}}\:\boldsymbol{{x}}}{\boldsymbol{{x}}^{\mathrm{4}} }\:\boldsymbol{{dx}}\:=\:\frac{\mathrm{1}}{\mathrm{9}} \\ $$ Answered by Ar Brandon last updated on 08/Jan/22…
Question Number 98020 by bobhans last updated on 11/Jun/20 $$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{region}\:\mathrm{bounded} \\ $$$$\mathrm{by}\:\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} \:\leqslant\:\mathrm{9}\:;\:\mathrm{x}+\mathrm{y}\:\leqslant\:\mathrm{3}\:\mathrm{and}\:\mathrm{y}\:\leqslant\:\mathrm{x}\: \\ $$ Answered by bemath last updated on 11/Jun/20 Commented by…