Menu Close

Category: Integration

Question-97059

Question Number 97059 by mhmd last updated on 06/Jun/20 Commented by PRITHWISH SEN 2 last updated on 06/Jun/20 $$\mathrm{let}\: \\ $$$$\:\:\:\frac{\mathrm{x}^{\mathrm{2}} +\mathrm{1}}{\mathrm{sin}^{−\mathrm{1}} \mathrm{x}−\mathrm{1}}\:=\:\mathrm{v}\left(\mathrm{x}\right) \\ $$$$\mathrm{then}\:\mathrm{v}^{'}…

0-1-dx-ln-x-by-Gamma-function-

Question Number 97057 by bemath last updated on 06/Jun/20 $$\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\:\frac{{dx}}{\:\sqrt{−\mathrm{ln}\left({x}\right)}}\:?\:\left[\:{by}\:{G}\mathrm{amma}\:\mathrm{function}\:\right] \\ $$ Answered by Sourav mridha last updated on 06/Jun/20 $$\boldsymbol{{let}}\:\boldsymbol{{ln}}\left(\boldsymbol{{x}}\right)=−\boldsymbol{{k}}.. \\ $$$$=\int_{\mathrm{0}}…

find-1-1-dx-1-x-1-x-

Question Number 31517 by abdo imad last updated on 09/Mar/18 $${find}\:\int_{−\mathrm{1}} ^{\mathrm{1}} \:\:\:\:\:\frac{{dx}}{\:\sqrt{\mathrm{1}+{x}}\:+\sqrt{\mathrm{1}−{x}}}\:\:. \\ $$ Commented by abdo imad last updated on 12/Mar/18 $${let}\:{put}\:{I}\left(\xi\right)\:=\int_{−\mathrm{1}+\xi} ^{\mathrm{1}+\xi}…

find-dx-x-1-x-2-

Question Number 31516 by abdo imad last updated on 09/Mar/18 $${find}\:\int\:\:\:\frac{{dx}}{{x}\:+\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }}\:. \\ $$ Commented by abdo imad last updated on 16/Mar/18 $${I}\:=\:\int\:\left(\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }\:−{x}\right){dx}=\:\int\:\sqrt{\mathrm{1}+{x}^{\mathrm{2}} \:}\:{dx}\:−\frac{{x}^{\mathrm{2}}…

g-is-real-function-continue-let-f-x-0-x-sin-x-t-g-t-dt-1-prove-that-f-x-0-x-cos-t-x-g-t-dt-2-prove-that-f-is-so-lt-ution-of-the-diff-equa-y-y-g-x-

Question Number 31507 by abdo imad last updated on 09/Mar/18 $${g}\:{is}\:{real}\:{function}\:{continue}\:{let} \\ $$$${f}\left({x}\right)=\int_{\mathrm{0}} ^{{x}} \:{sin}\left({x}−{t}\right){g}\left({t}\right){dt} \\ $$$$\left.\mathrm{1}\right){prove}\:{that}\:{f}^{'} \left({x}\right)=\:\int_{\mathrm{0}} ^{{x}} {cos}\left({t}−{x}\right){g}\left({t}\right){dt} \\ $$$$\left.\mathrm{2}\right){prove}\:{that}\:{f}\:{is}\:{so}<{ution}\:{of}\:{the}\:{diff}.{equa}. \\ $$$${y}^{''} \:+{y}\:={g}\left({x}\right)…