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Category: Integration

find-x-2-2-x-2-x-dx-

Question Number 98182 by abdomathmax last updated on 12/Jun/20 findx22x2+xdx Answered by MJS last updated on 12/Jun/20 x22x2+xdx=$$\:\:\:\:\:\left[{t}=\sqrt{\frac{\mathrm{2}+{x}}{\mathrm{2}−{x}}}\:\rightarrow\:{dx}=\frac{\mathrm{1}}{\mathrm{2}}\sqrt{\left(\mathrm{2}+{x}\right)\left(\mathrm{2}−{x}\right)^{\mathrm{3}} }{dt}\right]…