Menu Close

Category: Integration

Question-97707

Question Number 97707 by Power last updated on 09/Jun/20 Answered by smridha last updated on 09/Jun/20 $$=\frac{\mathrm{1}}{\mathrm{2}}\int_{−\infty} ^{+\infty} \frac{\boldsymbol{{e}}^{\boldsymbol{{ix}}} }{\boldsymbol{{x}}^{\mathrm{2}} +\mathrm{1}^{\mathrm{2}} }\boldsymbol{{dx}}\:+\frac{\mathrm{1}}{\mathrm{2}}\int_{+\infty} ^{−\infty} \frac{\boldsymbol{{e}}^{−\left(−\boldsymbol{{ix}}\right)} }{\left(−\boldsymbol{{x}}\right)^{\mathrm{2}}…