Question Number 30858 by gopikrishnan005@gmail.com last updated on 27/Feb/18 $$\int_{\mathrm{0}} ^{\mathrm{1}} \mathrm{x}\mid\mathrm{x}−\mathrm{4}\mid\mathrm{dx} \\ $$ Answered by mrW2 last updated on 27/Feb/18 $$\int_{\mathrm{0}} ^{\mathrm{1}} \mathrm{x}\mid\mathrm{x}−\mathrm{4}\mid\mathrm{dx} \\…
Question Number 96394 by mathmax by abdo last updated on 01/Jun/20 $$\mathrm{calculate}\:\int_{\mathrm{0}} ^{\infty} \:\frac{\mathrm{ln}\left(\mathrm{1}+\mathrm{x}\right).\mathrm{ln}\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{x}^{\mathrm{2}} }\right)}{\mathrm{x}}\mathrm{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 30855 by anunil1234 last updated on 27/Feb/18 $$\int\frac{\mathrm{cosec}^{\mathrm{2}} \left(\mathrm{x}\right)}{\:\sqrt{\mathrm{cosecx}+\mathrm{cotx}}}\mathrm{dx} \\ $$ Answered by math1967 last updated on 03/Mar/18 $$\int\frac{{Cosec}^{\mathrm{2}} {x}}{\:\sqrt{\frac{\mathrm{1}+{cosx}}{\mathrm{sin}\:{x}}}}{dx} \\ $$$$\int\frac{\sqrt{{tan}\frac{{x}}{\mathrm{2}}\:}}{{sin}^{\mathrm{2}} {x}}{dx}…
Question Number 161917 by talminator2856791 last updated on 24/Dec/21 $$\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\int_{−\infty} ^{\:\infty} \:\frac{\mathrm{1}}{\:\sqrt{{x}^{\mathrm{4}} +{x}+\mathrm{1}}\:}\:{dx} \\ $$$$\: \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 161919 by talminator2856791 last updated on 24/Dec/21 $$\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\int_{−\infty} ^{\:\infty} \:\mathrm{sin}\left({x}^{\mathrm{2}} +{x}+\mathrm{1}\right){dx}\: \\ $$$$\: \\ $$ Answered by Lordose last updated on…
Question Number 96373 by mathmax by abdo last updated on 01/Jun/20 $$\mathrm{1}.\:\mathrm{find}\:\int_{\mathrm{1}} ^{+\infty} \:\frac{\mathrm{dx}}{\mathrm{x}^{\mathrm{2}} −\mathrm{i}}\:\:\mathrm{and}\:\int_{\mathrm{1}} ^{+\infty} \:\frac{\mathrm{dx}}{\mathrm{x}^{\mathrm{2}} \:+\mathrm{i}}\:\:\:\:\left(\mathrm{i}=\sqrt{−\mathrm{1}}\right) \\ $$$$\mathrm{2}.\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\:\int_{\mathrm{1}} ^{+\infty} \:\frac{\mathrm{dx}}{\mathrm{x}^{\mathrm{4}} \:+\mathrm{1}} \\ $$…
Question Number 96365 by Ar Brandon last updated on 31/May/20 Answered by M±th+et+s last updated on 01/Jun/20 $${x}=\frac{\mathrm{1}}{{t}}\:\:\:{dx}=−\frac{{dt}}{{t}^{\mathrm{2}} } \\ $$$${I}=\int_{\infty} ^{\mathrm{0}} \frac{\frac{\mathrm{1}}{{t}^{\mathrm{2}} }.\left(−{ln}\left({t}\right)\right).\left(−\frac{{dt}}{{t}^{\mathrm{2}} }\right)}{\frac{\left(\mathrm{1}+{t}^{\mathrm{2}}…
Question Number 96346 by Ar Brandon last updated on 31/May/20 $$\int\frac{\mathrm{1}}{\mathfrak{ln}\left(\mathfrak{x}\right)}\boldsymbol{\mathrm{d}}\mathfrak{x} \\ $$ Commented by Tony Lin last updated on 01/Jun/20 $${let}\:{lnx}={t},\:{dx}={xdt}={e}^{{t}} {dt} \\ $$$$\int\:\frac{{e}^{{t}}…
Question Number 96342 by Ar Brandon last updated on 31/May/20 $$\int\mathfrak{e}^{\mathfrak{sin}\left(\mathfrak{x}\right)} \boldsymbol{\mathrm{d}}\mathfrak{x} \\ $$ Commented by prakash jain last updated on 31/May/20 $$\mathrm{You}\:\mathrm{should}\:\mathrm{clarify}\:\mathfrak{dx}\:\mathrm{notation}. \\ $$$$\mathrm{Are}\:\mathrm{you}\:\mathrm{asking}:…
Question Number 30798 by prof Abdo imad last updated on 25/Feb/18 $${find}\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\:\:\frac{{ln}\left(\mathrm{1}−{x}^{\mathrm{2}} \right)}{{x}^{\mathrm{2}} }{dx} \\ $$ Commented by prof Abdo imad last updated…