Question Number 98214 by me2love2math last updated on 12/Jun/20 Commented by mr W last updated on 12/Jun/20 $${A}=\frac{\mathrm{2}}{\mathrm{3}}×\mathrm{4}×\mathrm{4}=\frac{\mathrm{32}}{\mathrm{3}} \\ $$ Commented by mr W last…
Question Number 163751 by amin96 last updated on 10/Jan/22 $$\int_{\mathrm{0}} ^{\mathrm{1}} \boldsymbol{{ln}}\left(\mathrm{1}+\boldsymbol{{x}}\right)\boldsymbol{{ln}}\left(\mathrm{1}−\boldsymbol{{x}}\right)\boldsymbol{{dx}}=? \\ $$$$\boldsymbol{{by}}\:\boldsymbol{{MATH}}.\boldsymbol{{AMIN}} \\ $$$$−−−−−−−−−−−−−−−−−−−− \\ $$ Answered by Kamel last updated on 10/Jan/22…
Question Number 32675 by Cheyboy last updated on 31/Mar/18 Commented by caravan msup abdo. last updated on 31/Mar/18 $${we}\:{have}\:\mathrm{1}+{cos}\left(\mathrm{4}{x}\right)=\mathrm{2}{cos}^{\mathrm{2}} \left(\mathrm{2}{x}\right)\Rightarrow \\ $$$${I}=\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \:\sqrt{\mathrm{1}+{cos}\left(\mathrm{4}{x}\right)}\:{dx} \\…
Question Number 98182 by abdomathmax last updated on 12/Jun/20 $$\mathrm{find}\:\int\:\mathrm{x}^{\mathrm{2}} \sqrt{\frac{\mathrm{2}−\mathrm{x}}{\mathrm{2}+\mathrm{x}}}\mathrm{dx} \\ $$ Answered by MJS last updated on 12/Jun/20 $$\int{x}^{\mathrm{2}} \sqrt{\frac{\mathrm{2}−{x}}{\mathrm{2}+{x}}}{dx}= \\ $$$$\:\:\:\:\:\left[{t}=\sqrt{\frac{\mathrm{2}+{x}}{\mathrm{2}−{x}}}\:\rightarrow\:{dx}=\frac{\mathrm{1}}{\mathrm{2}}\sqrt{\left(\mathrm{2}+{x}\right)\left(\mathrm{2}−{x}\right)^{\mathrm{3}} }{dt}\right]…
Question Number 98181 by abdomathmax last updated on 12/Jun/20 $$\mathrm{calculate}\:\int_{\mathrm{0}} ^{\pi} \mathrm{ln}\left(\mathrm{x}^{\mathrm{2}} −\mathrm{2xcos}\theta\:+\mathrm{1}\right)\mathrm{d}\theta \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 98179 by abdomathmax last updated on 12/Jun/20 $$\mathrm{calculate}\:\int_{\mathrm{1}} ^{+\infty} \:\:\:\frac{\mathrm{dx}}{\mathrm{x}^{\mathrm{2}} \left(\mathrm{1}−\mathrm{x}^{\mathrm{2}} \right)^{\mathrm{3}} } \\ $$ Answered by MJS last updated on 12/Jun/20 $$\mathrm{I}\:\mathrm{love}\:\mathrm{Ostrogradski}'\mathrm{s}\:\mathrm{Method}……
Question Number 163709 by amin96 last updated on 09/Jan/22 $$\boldsymbol{\mathrm{CALCULUS}} \\ $$$$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\boldsymbol{\mathrm{x}}^{\mathrm{2}\boldsymbol{\mathrm{n}}−\mathrm{1}} }{\boldsymbol{\mathrm{x}}+\mathrm{1}}\boldsymbol{\mathrm{dx}}=?\:\:\:\:\:\boldsymbol{\mathrm{n}}\geqslant\mathrm{1} \\ $$ Answered by Mathspace last updated on 09/Jan/22 $$\int_{\mathrm{0}}…
Question Number 32627 by Cheyboy last updated on 29/Mar/18 $${plzz}\:{help}\:{ne}\:{differentiate}\: \\ $$$${between} \\ $$$$\int{sin}\left(\mathrm{2}{x}\right)=\:−\frac{\mathrm{1}}{\mathrm{2}}{cox}\left(\mathrm{2}{x}\right)+{c}\: \\ $$$${is}\:{not}\:{change}\:{to}\:\int\mathrm{2}{sin}\left({x}\right){cos}\left({x}\right) \\ $$$${but}\:\underset{{b}} {\overset{{a}} {\int}}{sin}\left(\mathrm{2}{x}\right)=\:{is}\:{change}\:{to} \\ $$$$\underset{{b}} {\overset{{a}} {\int}}\mathrm{2}{sin}\left({x}\right){cos}\left({x}\right) \\…
Question Number 163688 by mnjuly1970 last updated on 09/Jan/22 Answered by Lordose last updated on 13/Jan/22 Answered by Lordose last updated on 13/Jan/22 Terms of…
Question Number 98151 by M±th+et+s last updated on 11/Jun/20 $$\int{e}^{{x}^{\mathrm{5}} +\mathrm{8}{x}^{\mathrm{2}} } {dx} \\ $$$$=\frac{\sqrt{\pi}}{\mathrm{4}\sqrt{\mathrm{2}}}{e}^{{x}^{\mathrm{5}} } {erfi}\left(\mathrm{2}\sqrt{\mathrm{2}}{x}\right)−\frac{\mathrm{5}\sqrt{\pi}}{\mathrm{4}\left(\mathrm{128}\right)\sqrt{\mathrm{2}}}\left({super}−{erf}_{\left({hyper}\right)} \left(\mathrm{2}\sqrt{\mathrm{2}}{x}\right)\right)+{c} \\ $$$$ \\ $$$${where}\left[{super}−{erf}_{\left({hyper}\right)} \left({t}\right)\right]\:{is}\:{super}−{function} \\ $$$${in}\:{D}_{\mathrm{2}}…