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Category: Integration

1-x-3-3x-7-dx-

Question Number 197191 by tri26112004 last updated on 10/Sep/23 1x33x+7dx Answered by Frix last updated on 10/Sep/23 x33x+7=(xa)(x2+ax+b)$${a}=−\frac{\sqrt[{\mathrm{3}}]{\mathrm{7}+\mathrm{3}\sqrt{\mathrm{5}}}+\sqrt[{\mathrm{3}}]{\mathrm{7}−\mathrm{3}\sqrt{\mathrm{5}}}}{\:\sqrt[{\mathrm{3}}]{\mathrm{2}}};\:{b}=−\frac{\mathrm{7}}{{a}}…