Question Number 27615 by NECx last updated on 10/Jan/18 $$\int{x}^{\mathrm{5}/\mathrm{2}} \left(\mathrm{1}−{x}\right)^{\mathrm{3}/\mathrm{2}} {dx} \\ $$ Commented by abdo imad last updated on 11/Jan/18 $$\:{let}\:{do}\:{the}\:{changement}\:\:\:{x}\:={sin}^{\mathrm{2}} {t} \\…
Question Number 27613 by abdo imad last updated on 10/Jan/18 $${find}\:{the}\:{value}\:{of}\:\:\:\int_{\mathrm{0}} ^{\infty} \:\:{e}^{−\left[{x}\right]\:−{x}} {dx}\:\:. \\ $$ Commented by abdo imad last updated on 12/Jan/18 $${I}_{{n}}…
Question Number 27614 by NECx last updated on 10/Jan/18 $$\int\frac{{cosx}}{\mathrm{2}−{cosx}}{dx} \\ $$ Commented by abdo imad last updated on 11/Jan/18 $$\int\frac{{cosx}}{\mathrm{2}−{cosx}}{dx}=\:−\int\frac{\mathrm{2}−{cosx}\:+\mathrm{2}}{\mathrm{2}−{cosx}}{dx}\:=\:−{x}\:+\mathrm{2}\int\:\frac{{dx}}{\mathrm{2}−{cox}}\:\:{but} \\ $$$${the}\:{ch}.\:{tan}\left(\frac{{x}}{\mathrm{2}}\right)={t}\:{give}\: \\ $$$$\int\frac{{dx}}{\mathrm{2}−{cosx}}=\:\int\:\frac{\frac{\mathrm{2}{dt}}{\mathrm{1}+{t}^{\mathrm{2}}…
Question Number 27612 by NECx last updated on 10/Jan/18 $$\int\frac{\mathrm{1}}{\mathrm{3}+{cos}^{\mathrm{2}} {x}}{dx} \\ $$ Answered by ajfour last updated on 11/Jan/18 $$=\int\frac{\mathrm{sec}\:^{\mathrm{2}} {xdx}}{\mathrm{3sec}\:^{\mathrm{2}} {x}+\mathrm{1}}=\int\frac{{d}\left(\mathrm{tan}\:{x}\right)}{\mathrm{4}+\mathrm{3tan}\:^{\mathrm{2}} {x}} \\…
Question Number 93144 by i jagooll last updated on 11/May/20 $$\int\:\frac{\mathrm{x}^{\mathrm{3}} −\mathrm{1}}{\mathrm{x}^{\mathrm{3}} +\mathrm{6x}^{\mathrm{2}} +\mathrm{10x}}\:\mathrm{dx}\: \\ $$ Answered by MJS last updated on 11/May/20 $$\frac{{x}^{\mathrm{3}} −\mathrm{1}}{{x}\left({x}^{\mathrm{2}}…
Question Number 27611 by NECx last updated on 10/Jan/18 $$\int\frac{\mathrm{1}}{\mathrm{2sin}\:^{\mathrm{2}} {x}\:+\:\mathrm{4cos}\:^{\mathrm{2}} {x}}{dx} \\ $$ Answered by ajfour last updated on 11/Jan/18 $$=\int\frac{\mathrm{sec}\:^{\mathrm{2}} {xdx}}{\mathrm{2tan}\:^{\mathrm{2}} {x}+\mathrm{4}}=\int\frac{{dt}}{\mathrm{2}{t}^{\mathrm{2}} +\mathrm{4}}\:\:;\left({t}=\mathrm{tan}\:{x}\right)…
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Question Number 27600 by abdo imad last updated on 10/Jan/18 $${find}\:\:\:\int_{\mathrm{0}} ^{\pi} \:\:\frac{{t}}{\mathrm{2}+{sint}}\:{dt} \\ $$ Commented by abdo imad last updated on 11/Jan/18 $${let}\:{put}\:{I}=\int_{\mathrm{0}} ^{\pi}…
Question Number 158674 by cortano last updated on 07/Nov/21 Commented by tounghoungko last updated on 07/Nov/21 $${I}_{\mathrm{1}} =\int\:\frac{{dx}}{\:\sqrt[{\mathrm{3}}]{{x}}+\sqrt[{\mathrm{4}}]{{x}}}\:;\:{x}={r}^{\mathrm{12}} \\ $$$${I}_{\mathrm{1}} =\int\:\frac{\mathrm{12}{r}^{\mathrm{11}} }{{r}^{\mathrm{4}} +{r}^{\mathrm{3}} }\:{dr}=\int\:\frac{\mathrm{12}{r}^{\mathrm{8}} }{{r}+\mathrm{1}}\:{dr}…
Question Number 27597 by abdo imad last updated on 10/Jan/18 $${find}\:\int\:\:\frac{\sqrt{{cos}\left(\mathrm{2}{x}\right)}}{{cosx}}\:{dx}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com