Question Number 160328 by cortano last updated on 27/Nov/21 $$\:\int_{\mathrm{1}} ^{\:\mathrm{2e}} \:\sqrt{\frac{\mathrm{x}^{\mathrm{2}} +\mathrm{1}}{\mathrm{ln}\:\mathrm{x}}\:\sqrt{\mathrm{ln}\:\mathrm{x}^{\mathrm{2}} }}\:\mathrm{dx}\:=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 94752 by mhmd last updated on 20/May/20 $${Find}\:{the}\:{volume}\:{of}\:{the}\:{region}\:{bounded}\:{above}\:{by}\:{the}\:{surface}\:{z}={x} \\ $$$${and}\:{below}\:{by}\:{the}\:{region}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} −\mathrm{2}{y}=\mathrm{0}\:? \\ $$$${pleas}\:{sir}\:{can}\:{you}\:{help}\:{me}\:{becouse}\:{im}\:{very}\:{nedd}\:? \\ $$ Commented by mhmd last updated on 21/May/20…
Question Number 160291 by cortano last updated on 27/Nov/21 $$\:\:\:\Omega\:=\:\int\:\frac{\mathrm{x}^{\mathrm{2}} −\mathrm{3x}+\mathrm{7}}{\left(\mathrm{x}^{\mathrm{2}} −\mathrm{4x}+\mathrm{6}\right)^{\mathrm{2}} }\:\mathrm{dx}\:=? \\ $$ Answered by 2970604Lu last updated on 27/Nov/21 $$ \\ $$$$…
Question Number 160281 by amin96 last updated on 27/Nov/21 $$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\boldsymbol{\mathrm{ln}}^{\mathrm{2}} \left(\mathrm{1}−\boldsymbol{\mathrm{x}}\right)\boldsymbol{\mathrm{lnx}}}{\boldsymbol{\mathrm{x}}}\boldsymbol{\mathrm{dx}}=? \\ $$ Answered by TheSupreme last updated on 27/Nov/21 $$\int_{\mathrm{0}} ^{\mathrm{1}} {ln}^{\mathrm{2}}…
Question Number 160276 by amin96 last updated on 27/Nov/21 $$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\boldsymbol{\mathrm{ln}}\left(\mathrm{1}−\boldsymbol{\mathrm{x}}\right)\boldsymbol{\mathrm{ln}}\left(\boldsymbol{\mathrm{x}}\right)}{\mathrm{1}−\boldsymbol{\mathrm{x}}}\boldsymbol{\mathrm{dx}}=? \\ $$ Answered by mnjuly1970 last updated on 27/Nov/21 $$\:\:\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{\:{ln}\left({x}\right).{ln}\left(\mathrm{1}−{x}\right)}{{x}}{dx}=\:\left[−{li}_{\mathrm{2}} \left({x}\right).{ln}\left({x}\right)\right]_{\mathrm{0}}…
Question Number 29202 by ajfour last updated on 05/Feb/18 $${Find}\:{area}\:{between}\:{by}\:{y}=\mathrm{1}\:\:{and} \\ $$$${y}=\frac{\mathrm{1}−{x}^{\mathrm{2}} }{\mathrm{1}+{x}^{\mathrm{2}} }\:. \\ $$ Answered by mrW2 last updated on 05/Feb/18 $${y}=\frac{\mathrm{1}−{x}^{\mathrm{2}} }{\mathrm{1}+{x}^{\mathrm{2}}…
Question Number 94735 by student work last updated on 20/May/20 $$\int\frac{\mathrm{2t}}{\left(\mathrm{1}+\mathrm{t}^{\mathrm{4}} \right)\left(\mathrm{1}+\mathrm{t}\right)}\mathrm{dt}=? \\ $$ Commented by student work last updated on 20/May/20 $$\mathrm{who}\:\mathrm{can}\:\mathrm{another}? \\ $$…
Question Number 94718 by john santu last updated on 20/May/20 $$\int\:\sqrt{\mathrm{tan}\:\mathrm{x}}\:\mathrm{dx}\:= \\ $$$$\int\frac{\sqrt{\mathrm{tan}\:\mathrm{x}}+\sqrt{\mathrm{cot}\:\mathrm{x}}}{\mathrm{2}}\:\mathrm{dx}\:+\:\int\:\frac{\sqrt{\mathrm{tan}\:\mathrm{x}}−\sqrt{\mathrm{cot}\:\mathrm{x}}}{\mathrm{2}}\:\mathrm{dx} \\ $$$$=\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}\:}\int\:\frac{\mathrm{sin}\:\mathrm{x}+\mathrm{cos}\:\mathrm{x}}{\:\sqrt{\mathrm{sin}\:\mathrm{2x}}}\:\mathrm{dx}\:+\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}\:}\int\:\frac{\mathrm{sin}\:\mathrm{x}−\mathrm{cos}\:\mathrm{x}}{\:\sqrt{\mathrm{sin}\:\mathrm{2x}}}\:\mathrm{dx} \\ $$$$=\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}\:}\int\:\frac{\mathrm{sin}\:\mathrm{x}+\mathrm{cos}\:\mathrm{x}}{\:\sqrt{\mathrm{1}−\left(\mathrm{sin}\:\mathrm{x}−\mathrm{cos}\:\mathrm{x}\right)^{\mathrm{2}} }}\:\mathrm{dx}\:+\: \\ $$$$\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\:\int\:\frac{\mathrm{sin}\:\mathrm{x}−\mathrm{cos}\:\mathrm{x}}{\:\sqrt{\left(\mathrm{sin}\:\mathrm{x}+\mathrm{cos}\:\mathrm{x}\right)^{\mathrm{2}} −\mathrm{1}}}\:\mathrm{dx}\: \\ $$$$=\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}\:}\int\:\frac{\mathrm{dt}}{\:\sqrt{\mathrm{1}−\mathrm{t}^{\mathrm{2}} }}\:+\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}\:}\int\:\frac{−\mathrm{du}}{\:\sqrt{\mathrm{u}^{\mathrm{2}} −\mathrm{1}}}…
Question Number 94701 by i jagooll last updated on 20/May/20 $$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{volume}\:\mathrm{of}\:\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} +\mathrm{z}^{\mathrm{2}} =\mathrm{2} \\ $$$$ \\ $$ Commented by mr W last updated on…
Question Number 29162 by abdo imad last updated on 04/Feb/18 $${find}\:\:{find}\:{I}=\:\int_{\mathrm{1}} ^{\mathrm{3}} \:\:\:\:\frac{\mid{x}−\mathrm{2}\mid}{\left({x}^{\mathrm{2}} −\mathrm{4}{x}\right)^{\mathrm{2}} }{dx}\:. \\ $$ Commented by abdo imad last updated on 06/Feb/18…