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Category: Integration

n-0-arctan-1-n-2n-1-

Question Number 158822 by qaz last updated on 09/Nov/21 n=0arctan(1)n2n+1=? Answered by mindispower last updated on 09/Nov/21 $$\underset{{n}\geqslant\mathrm{0}} {\sum}\left\{{arctan}\left(\frac{\mathrm{1}}{\mathrm{4}{n}+\mathrm{1}}\right)−{arctan}\left(\frac{\mathrm{1}}{\mathrm{4}{n}+\mathrm{3}}\right)\right\} \