Question Number 155933 by talminator2856791 last updated on 09/Oct/21 $$\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\int_{−\infty} ^{\:\infty} \:\frac{\sqrt{\mathrm{1}+\:\frac{\mathrm{1}}{{x}^{\mathrm{2}} +\mathrm{1}}\:}\:}{{x}^{\mathrm{2}} +\:{x}\:+\mathrm{1}}\:{dx} \\ $$$$\: \\ $$ Commented by talminator2856791 last updated…
Question Number 155929 by talminator2856791 last updated on 06/Oct/21 $$\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\int_{\mathrm{1}} ^{\:\mathrm{2}} \:\frac{\sqrt{{x}^{\mathrm{2}} }}{\mathrm{ln}\left({x}^{\mathrm{2}} \right)}\:{dx} \\ $$$$\: \\ $$ Terms of Service Privacy Policy…
Question Number 155930 by talminator2856791 last updated on 06/Oct/21 $$\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\int_{\mathrm{0}} ^{\:\mathrm{1}} \:\:\frac{\mathrm{sin}\left({x}\right)\mathrm{cos}\left({x}\right)}{\mathrm{sin}^{\mathrm{3}} \left({x}\right)+\mathrm{cos}^{\mathrm{3}} \left({x}\right)}\:{dx} \\ $$$$\: \\ $$ Commented by talminator2856791 last updated…
Question Number 24852 by nnnavendu last updated on 27/Nov/17 $$\mathrm{please}\:\mathrm{prove}\:\mathrm{that}\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \mathrm{log}\left(\mathrm{sinx}\right)\mathrm{dx}=−\frac{\pi}{\mathrm{2}}\mathrm{log2} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{or} \\ $$$$\int_{\mathrm{0}} ^{\frac{\pi\:\:}{\mathrm{2}}} \mathrm{log}\left(\mathrm{cosx}\right)\mathrm{dx}=−\frac{\pi}{\mathrm{2}}\mathrm{log2} \\ $$ Commented by Tinku Tara last…
Question Number 155919 by horpy4 last updated on 05/Oct/21 Answered by physicstutes last updated on 05/Oct/21 $$\boldsymbol{\mathrm{F}}×\boldsymbol{\mathrm{V}}\:=\:\begin{vmatrix}{{i}}&{{j}}&{{k}}\\{\mathrm{3}{u}}&{{u}^{\mathrm{2}} }&{{u}+\mathrm{2}}\\{\mathrm{2}{u}}&{−\mathrm{3}{u}}&{{u}−\mathrm{2}}\end{vmatrix}={i}\left({u}^{\mathrm{3}} −\mathrm{2}{u}^{\mathrm{2}} +\mathrm{3}{u}^{\mathrm{2}} −\mathrm{6}{u}\right) \\ $$$$−\:{j}\left(\mathrm{3}{u}^{\mathrm{2}} −\mathrm{6}{u}−\mathrm{2}{u}^{\mathrm{2}} −\mathrm{4}{u}\right)\:+\:{k}\left(−\mathrm{9}{u}^{\mathrm{2}}…
Question Number 24828 by moxhix last updated on 27/Nov/17 $$\int\sqrt{{e}^{{x}} +\mathrm{1}}{dx}=? \\ $$ Commented by mrW1 last updated on 27/Nov/17 $${see}\:{Q}\mathrm{24670} \\ $$ Commented by…
Question Number 155897 by cortano last updated on 05/Oct/21 $$\:\int\:\mathrm{x}\left(\mathrm{arctan}\:\mathrm{x}\right)^{\mathrm{2}} \:\mathrm{dx}=? \\ $$ Answered by puissant last updated on 05/Oct/21 $${Q}=\int{x}\left({arctanx}\right)^{\mathrm{2}} {dx}.. \\ $$$${IBP}\:\:\Rightarrow\:.. \\…
Question Number 24825 by A1B1C1D1 last updated on 27/Nov/17 $$\int_{\mathrm{0}} ^{\:\mathrm{2}} \int_{\mathrm{x}} ^{\:\:\mathrm{3x}\:−\:\mathrm{x}^{\mathrm{2}} } \:\mathrm{6x}^{\mathrm{2}} \:−\:\mathrm{2xy}\:\mathrm{dy}\:\mathrm{dx}\:=\:? \\ $$ Commented by 1kanika# last updated on 27/Nov/17…
Question Number 24817 by A1B1C1D1 last updated on 26/Nov/17 Answered by mrW1 last updated on 26/Nov/17 $$=\int_{\mathrm{0}} ^{\:\mathrm{4}} \left[\frac{\mathrm{1}}{\mathrm{2}}\left({y}−\frac{{y}^{\mathrm{2}} }{\mathrm{16}}\right)+{y}\left(\sqrt{{y}}−\frac{{y}}{\mathrm{4}}\right)\right]{dy} \\ $$$$=\int_{\mathrm{0}} ^{\:\mathrm{4}} \left(\frac{{y}}{\mathrm{2}}−\frac{\mathrm{9}{y}^{\mathrm{2}} }{\mathrm{32}}+{y}^{\frac{\mathrm{3}}{\mathrm{2}}}…
Question Number 90357 by john santu last updated on 23/Apr/20 $$\int\:\frac{{x}.\mathrm{2}^{{x}} }{\:\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }}\:{dx}\:=\:? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com