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Question Number 156182 by cortano last updated on 09/Oct/21 Answered by PRITHWISH SEN 2 last updated on 10/Oct/21 $$\int\frac{\mathrm{sec}^{\mathrm{4}} \mathrm{xdx}}{\mathrm{12tan}\:^{\mathrm{2}} \mathrm{x}−\mathrm{4}}\:=\:\int\frac{\mathrm{sec}^{\mathrm{2}} \mathrm{x}\left(\mathrm{1}+\mathrm{tan}\:^{\mathrm{2}} \mathrm{x}\right)\mathrm{dx}}{\mathrm{12tan}\:^{\mathrm{2}} \mathrm{x}−\mathrm{4}} \…