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Category: Integration

Question-87969

Question Number 87969 by M±th+et£s last updated on 07/Apr/20 Answered by mind is power last updated on 07/Apr/20 $$=\underset{{k}\geqslant\mathrm{1}} {\sum}\int_{{k}} ^{\frac{\mathrm{2}{k}+\mathrm{1}}{\mathrm{2}}} \frac{\sqrt{\left.{x}−\lfloor{x}\right]}}{\left[\mathrm{2}{x}\right]^{\mathrm{2}} }{d}\underset{={S}} {{x}}+\underset{{k}\geqslant\mathrm{1}} {\sum}\int_{\frac{\mathrm{2}{k}+\mathrm{1}}{\mathrm{2}}}…