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Question Number 64122 by mmkkmm000m last updated on 13/Jul/19 $$\int{tan}\left(\mathrm{1}/{x}\right){dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 64121 by mmkkmm000m last updated on 13/Jul/19 $$\int{tan}\left(\mathrm{1}/{x}\right){dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 129651 by mnjuly1970 last updated on 17/Jan/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:…\:{nice}\:\:\:{calculus}… \\ $$$$\:\:\:\:{evaluate}\::: \\ $$$$\:\:\:\:\:\:\:\:\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\:\frac{\left(−\mathrm{1}\right)^{{n}} }{{n}^{\mathrm{2}} +\mathrm{1}}\:\left(\frac{{sin}\left({n}\right)}{{n}}\right)^{\mathrm{2}} =? \\ $$$$ \\ $$ Terms of…
Question Number 129646 by liberty last updated on 17/Jan/21 $$\:\:\digamma\:=\:\int\:\frac{{dx}}{{x}^{\mathrm{2}{n}+\mathrm{1}} \left({x}^{{n}} −\mathrm{1}\right)} \\ $$ Answered by TheSupreme last updated on 17/Jan/21 $${x}^{{n}} ={t} \\ $$$${x}={t}^{\frac{\mathrm{1}}{{n}}}…
Question Number 129645 by liberty last updated on 17/Jan/21 $$\:\:\:\:\digamma\:=\:\int\:\frac{{dx}}{\mathrm{1}+{x}^{\mathrm{12}} }\:. \\ $$ Answered by mathmax by abdo last updated on 17/Jan/21 $$\mathrm{roots}\:\mathrm{of}\:\mathrm{z}^{\mathrm{12}} +\mathrm{1}=\mathrm{0}\:\:\:\Rightarrow\mathrm{z}^{\mathrm{12}} \:=\mathrm{e}^{\mathrm{i}\pi\:+\mathrm{2ik}\pi}…
Question Number 64106 by mmkkmm000m last updated on 13/Jul/19 $$\int{tan}\left(\mathrm{1}/{x}\right){dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 64105 by mmkkmm000m last updated on 13/Jul/19 $$\int{tan}\left(\mathrm{1}/{x}\right){dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 64103 by mmkkmm000m last updated on 13/Jul/19 $$\int{tan}\left(\mathrm{1}/{x}\right){dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 64104 by mmkkmm000m last updated on 13/Jul/19 $$\int{tan}\left(\mathrm{1}/{x}\right){dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com