Menu Close

Category: Integration

6e-x-e-2x-1-dx-

Question Number 86998 by M±th+et£s last updated on 01/Apr/20 $$\int\frac{\mathrm{6}{e}^{{x}} }{{e}^{\mathrm{2}{x}} −\mathrm{1}}\:{dx} \\ $$ Answered by TANMAY PANACEA. last updated on 01/Apr/20 $$\int\frac{\mathrm{6}{d}\left({e}^{{x}} \right)}{\left({e}^{{x}} +\mathrm{1}\right)\left({e}^{{x}}…

Question-152533

Question Number 152533 by mnjuly1970 last updated on 29/Aug/21 Answered by Kamel last updated on 29/Aug/21 $${I}\overset{{t}=\sqrt{{x}}} {=}\mathrm{2}\int_{\mathrm{0}} ^{+\infty} \frac{{Ln}\left(\mathrm{1}+{t}\right)}{{t}\left(\mathrm{1}+{t}\right)}{dt}=\mathrm{2}\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{Ln}\left(\mathrm{1}+{t}\right)}{{t}\left(\mathrm{1}+{t}\right)}{dt}+\mathrm{2}\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{Ln}\left(\mathrm{1}+{t}\right)−{Ln}\left({t}\right)}{\mathrm{1}+{t}}{dt} \\…

Question-86993

Question Number 86993 by Power last updated on 01/Apr/20 Commented by abdomathmax last updated on 01/Apr/20 $${I}\:=\int_{\mathrm{1}} ^{\mathrm{5}} \left[\mathrm{10}{x}\right]{dx}\:\:{vhangement}\:\mathrm{10}{x}\:={t}\:{give} \\ $$$${I}\:=\frac{\mathrm{1}}{\mathrm{10}}\:\int_{\mathrm{10}} ^{\mathrm{50}} \left[{t}\right]{dt}\:=\frac{\mathrm{1}}{\mathrm{10}}\sum_{{k}=\mathrm{10}} ^{\mathrm{49}} \:\int_{{k}}…

9x-2-4x-2-3-10-dx-

Question Number 152502 by Tawa11 last updated on 29/Aug/21 $$\int\:\mathrm{9x}^{\mathrm{2}} \left(\mathrm{4x}^{\mathrm{2}} \:\:+\:\:\mathrm{3}\right)^{\mathrm{10}} \:\mathrm{dx} \\ $$ Answered by Olaf_Thorendsen last updated on 30/Aug/21 $$\mathrm{F}\left({x}\right)\:=\:\int\mathrm{9}{x}^{\mathrm{2}} \left(\mathrm{4}{x}^{\mathrm{2}} +\mathrm{3}\right)^{\mathrm{10}}…