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Category: Integration

k-0-4-k-k-k-

Question Number 154824 by talminator2856791 last updated on 21/Sep/21 $$\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\underset{{k}=\mathrm{0}} {\overset{\infty} {\sum}}\:\frac{\mathrm{4}^{−{k}} \Gamma\left({k}\right)}{{k}!} \\ $$$$\: \\ $$ Answered by Ar Brandon last updated…

Evaluate-0-1-x-2-1-x-3-dx-and-given-that-I-n-0-1-x-n-1-x-3-1-2-dx-show-that-2n-1-I-n-2-2-2-n-1-for-n-3-Hence-evaluate-I-8-I-7-and-I-6-

Question Number 89273 by Ar Brandon last updated on 16/Apr/20 $${Evaluate}\:\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{x}^{\mathrm{2}} }{\:\sqrt{\mathrm{1}+{x}^{\mathrm{3}} }}{dx}\:{and}\:{given}\:{that}\:{I}_{{n}\:} =\int_{\mathrm{0}} ^{\mathrm{1}} {x}^{{n}} \left(\mathrm{1}+{x}^{\mathrm{3}} \right)^{−\frac{\mathrm{1}}{\mathrm{2}}} {dx} \\ $$$${show}\:{that}\:\left(\mathrm{2}{n}−\mathrm{1}\right){I}_{{n}} =\mathrm{2}\sqrt{\mathrm{2}}−\mathrm{2}\left({n}−\mathrm{1}\right)\:{for}\:{n}\geqslant\mathrm{3}. \\…

2-1-x-1-x-3-

Question Number 89237 by cindiaulia last updated on 16/Apr/20 $$\int_{\mathrm{2}} ^{\mathrm{1}} \left(\mathrm{x}+\mathrm{1}\right)\left(\sqrt{\left.\mathrm{x}+\mathrm{3}\right)}\right. \\ $$ Commented by niroj last updated on 16/Apr/20 $$=\:\int_{\mathrm{2}} ^{\mathrm{1}} \left(\mathrm{x}+\mathrm{1}\right)\sqrt{\mathrm{x}+\mathrm{3}}\:\:\mathrm{dx} \\…

4-5-x-2-x-4-

Question Number 89228 by cindiaulia last updated on 16/Apr/20 $$\underset{\mathrm{4}} {\overset{\mathrm{5}} {\int}}\mathrm{x}^{\mathrm{2}} \sqrt{\mathrm{x}−\mathrm{4}} \\ $$ Commented by jagoll last updated on 16/Apr/20 $$\sqrt{{x}−\mathrm{4}}\:=\:{t}\:\Rightarrow{x}={t}^{\mathrm{2}} +\mathrm{4} \\…

x-3-2-x-3-x-1-x-2-

Question Number 89226 by cindiaulia last updated on 16/Apr/20 $$\int\left(\frac{\mathrm{x}^{\mathrm{3}} +\mathrm{2}}{\mathrm{x}^{\mathrm{3}} }\right)\sqrt{\mathrm{x}−\frac{\mathrm{1}}{\mathrm{x}^{\mathrm{2}} }} \\ $$ Commented by jagoll last updated on 16/Apr/20 $$\int\:\left(\mathrm{1}+\frac{\mathrm{2}}{{x}^{\mathrm{3}} }\right)\:\sqrt{{x}−\frac{\mathrm{1}}{{x}^{\mathrm{2}} }}\:{dx}\:…