Menu Close

Category: Integration

1-4u-4u-2-2u-2-du-

Question Number 85591 by sahnaz last updated on 23/Mar/20 1+4u4u2+2u+2du Answered by john santu last updated on 23/Mar/20 $$−\frac{\mathrm{1}}{\mathrm{2}}\int\:\frac{\mathrm{2}}{\mathrm{3}\left(\mathrm{2}{u}+\mathrm{1}\right)}{du}+\int\:\frac{\mathrm{5}}{\mathrm{3}\left({u}−\mathrm{1}\right)}{du} \