Menu Close

Category: Integration

cos-xe-sin-x-dx-

Question Number 83115 by 09658867628 last updated on 28/Feb/20 $$\int\mathrm{cos}\:{xe}^{\mathrm{sin}\:{x}} {dx} \\ $$ Commented by niroj last updated on 28/Feb/20 $$ \\ $$$$\:\int\boldsymbol{\mathrm{cos}}\:\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{e}}^{\boldsymbol{\mathrm{sin}}\:\boldsymbol{\mathrm{x}}} \boldsymbol{\mathrm{dx}} \\…

prove-that-0-pi-4-cos-nx-cos-n-x-dx-2-n-pi-8-k-1-n-1-sin-kpi-4-2k-2-k-n-N-

Question Number 83108 by M±th+et£s last updated on 28/Feb/20 $${prove}\:{that} \\ $$$$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \frac{{cos}\left({nx}\right)}{{cos}^{{n}} \left({x}\right)}\:{dx}\:=\mathrm{2}^{{n}} \left[\frac{\pi}{\mathrm{8}}−\underset{{k}=\mathrm{1}} {\overset{{n}−\mathrm{1}} {\sum}}\frac{{sin}\left(\frac{{k}\pi}{\mathrm{4}}\right)}{\mathrm{2}{k}\left(\sqrt{\mathrm{2}}\right)^{{k}} }\right]\:{n}\in{N}^{\ast} \\ $$ Answered by mind is…

bounded-by-the-curve-y-4-x-y-0-y-1-

Question Number 83110 by 09658867628 last updated on 28/Feb/20 $${bounded}\:{by}\:{the}\:{curve}\:{y}=\sqrt{\mathrm{4}-{x}}\:{y}=\mathrm{0}\:{y}=\mathrm{1} \\ $$ Commented by jagoll last updated on 28/Feb/20 $$\mathrm{Area}\:=\:\int_{\mathrm{0}} ^{\mathrm{1}} \left(\mathrm{4}−\mathrm{y}^{\mathrm{2}} \right)\:\mathrm{dy}\: \\ $$$$=\:\mathrm{4y}\:−\:\frac{\mathrm{y}^{\mathrm{3}}…

1-e-e-dt-t-

Question Number 83109 by 09658867628 last updated on 28/Feb/20 $$\int_{\mathrm{1}/\boldsymbol{{e}}} ^{{e}} \frac{\boldsymbol{{dt}}}{\boldsymbol{{t}}} \\ $$ Commented by jagoll last updated on 28/Feb/20 $$=\:\mathrm{ln}\:\left(\mathrm{t}\right)\:\mid_{\frac{\mathrm{1}}{\mathrm{e}}} ^{\mathrm{e}} \:=\:\mathrm{1}−\left(−\mathrm{1}\right)\:=\:\mathrm{2} \\…