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Category: Integration

tan-x-1-3-dx-

Question Number 84709 by M±th+et£s last updated on 15/Mar/20 tan(x)3dx Answered by MJS last updated on 15/Mar/20 tanx3dx=$$\:\:\:\:\:\left[{t}=\left(\mathrm{tan}\:{x}\right)^{\mathrm{2}/\mathrm{3}} \:\rightarrow\:{dx}=\frac{\mathrm{3}}{\mathrm{2}}\left(\mathrm{sin}\:{x}\right)^{\mathrm{1}/\mathrm{3}} \left(\mathrm{cos}\:{x}\right)^{\mathrm{5}/\mathrm{3}} {dt}\right]…

Question-84681

Question Number 84681 by Power last updated on 15/Mar/20 Commented by mathmax by abdo last updated on 15/Mar/20 I=15sinx+2cosx98sinx7cosxdxI=1598sinx+215cosxsinx798cosxdxletdetermineA=sinx+acosxsinx+bcosxdxwedithechangement$${tan}\left(\frac{{x}}{\mathrm{2}}\right)={t}\:\Rightarrow\:{A}\:=\int\frac{\frac{\mathrm{2}{t}}{\mathrm{1}+{t}^{\mathrm{2}} }+{a}\frac{\mathrm{1}−{t}^{\mathrm{2}} }{\mathrm{1}+{t}^{\mathrm{2}}…

sec-3-x-dx-

Question Number 19077 by Joel577 last updated on 04/Aug/17 sec3xdx Answered by ajfour last updated on 04/Aug/17 I=secθ(sec2θdθ)$$=\mathrm{sec}\:\theta\int\mathrm{sec}\:^{\mathrm{2}} \theta\mathrm{d}\theta−\int\left[\frac{\mathrm{d}}{\mathrm{d}\theta}\left(\mathrm{sec}\:\theta\right).\int\mathrm{sec}\:^{\mathrm{2}}…