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Category: Integration

sin-7x-cos-3x-dx-

Question Number 84843 by M±th+et£s last updated on 16/Mar/20 sin(7x)cos(3x)dx Commented by jagoll last updated on 17/Mar/20 sin7x=sin(4x+3x)=sin4xcos3x+cos4xsin3x$$\int\:\frac{\mathrm{sin}\:\mathrm{7x}}{\mathrm{cos}\:\mathrm{3x}}\:\mathrm{dx}\:=\:\int\:\left(\mathrm{sin}\:\mathrm{4x}\:+\:\mathrm{cos}\:\mathrm{4x}\:\mathrm{tan}\:\mathrm{3x}\right)\mathrm{dx} \