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Category: Integration

0-dx-3-2sinx-cosx-

Question Number 17034 by arnabpapu550@gmail.com last updated on 30/Jun/17 $$\int_{\mathrm{0}} ^{\:\Pi} \frac{\mathrm{dx}}{\mathrm{3}+\mathrm{2sinx}+\mathrm{cosx}} \\ $$ Answered by Arnab Maiti last updated on 03/Jul/17 $$=\int_{\mathrm{0}} ^{\:\Pi} \frac{\mathrm{dx}}{\mathrm{3}+\mathrm{2}×\frac{\mathrm{2tan}\frac{\mathrm{x}}{\mathrm{2}}}{\mathrm{1}+\mathrm{tan}^{\mathrm{2}}…

cot-2-x-3-dx-

Question Number 17030 by tawa tawa last updated on 29/Jun/17 $$\int\:\mathrm{cot}^{\mathrm{2}} \left(\mathrm{x}^{\mathrm{3}} \right)\:\mathrm{dx} \\ $$ Commented by Arnab Maiti last updated on 03/Jul/17 $$\mathrm{How}\:\mathrm{is}\:\mathrm{it}\:\mathrm{possible}\:?\:\int\mathrm{x}^{\mathrm{2}} \mathrm{cot}^{\mathrm{2}}…

x-1-x-dx-

Question Number 82566 by jagoll last updated on 22/Feb/20 $$\int\:\sqrt{\frac{{x}+\mathrm{1}}{{x}}}\:{dx}\:=\:? \\ $$ Commented by mathmax by abdo last updated on 22/Feb/20 $${let}\:{I}=\int\sqrt{\frac{{x}+\mathrm{1}}{{x}}}{dx}\:{changement}\:\sqrt{\frac{{x}+\mathrm{1}}{{x}}}={t}\:{give}\:\frac{{x}+\mathrm{1}}{{x}}={t}^{\mathrm{2}} \:\Rightarrow \\ $$$${x}+\mathrm{1}\:={xt}^{\mathrm{2}}…

Use-gamma-function-to-prove-i-0-pi-4-sin-4-x-2x-dx-3-4-192-ii-0-pi-6-cos-4-3-sin-2-6-5pi-192-

Question Number 82560 by niroj last updated on 22/Feb/20 $$\:\boldsymbol{\mathrm{U}}\mathrm{se}\:\mathrm{gamma}\:\mathrm{function}\:\mathrm{to}\:\mathrm{prove} \\ $$$$\:\:\left(\mathrm{i}\right)\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \boldsymbol{\mathrm{sin}}^{\mathrm{4}} \boldsymbol{\mathrm{x}}\:\mathrm{2}\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{dx}}\:=\:\frac{\mathrm{3}\boldsymbol{\pi}−\mathrm{4}}{\mathrm{192}}. \\ $$$$\:\:\left(\mathrm{ii}\right)\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{6}}} \:\boldsymbol{\mathrm{cos}}^{\mathrm{4}} \mathrm{3}\boldsymbol{\theta}\:\mathrm{sin}^{\mathrm{2}} \mathrm{6}\theta\:=\:\frac{\mathrm{5}\pi}{\mathrm{192}}. \\ $$ Answered by…

1-2-1-x-2-sin-1-x-dx-

Question Number 17008 by arnabpapu550@gmail.com last updated on 29/Jun/17 $$\int_{\frac{\mathrm{1}\:}{\Pi}} ^{\frac{\mathrm{2}}{\Pi}} \:\frac{\mathrm{1}}{\mathrm{x}^{\mathrm{2}} }\mathrm{sin}\frac{\mathrm{1}}{\mathrm{x}}\mathrm{dx} \\ $$ Answered by sma3l2996 last updated on 29/Jun/17 $${t}=\frac{\mathrm{1}}{{x}}\Rightarrow{dt}=\frac{−{dx}}{{x}^{\mathrm{2}} } \\…