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Category: Integration

Question-147746

Question Number 147746 by 0731619 last updated on 23/Jul/21 Answered by mindispower last updated on 23/Jul/21 $$\frac{{tan}^{−} \left({x}^{\mathrm{2}} \right)}{{tan}^{−} \left({x}\right)}<\mathrm{1} \\ $$$${x}\leqslant{x}^{\mathrm{2}} <\mathrm{1},\:{and}\:{using}\:{tan}^{−} \:{increasing}\:{function} \\…

dx-sec-x-csc-x-

Question Number 82185 by jagoll last updated on 19/Feb/20 $$\int\:\frac{{dx}}{\mathrm{sec}\:{x}\:+\:{csc}\:{x}}\:=\:?\: \\ $$ Commented by john santu last updated on 19/Feb/20 $$\mathrm{sec}\:{x}+\:{csc}\:{x}\:=\:\frac{\mathrm{1}}{\mathrm{cos}\:{x}}+\frac{\mathrm{1}}{\mathrm{sin}\:{x}} \\ $$$$\frac{\mathrm{sin}\:{x}+\mathrm{cos}\:{x}}{\mathrm{sin}\:{x}\:\mathrm{cos}\:{x}}\:. \\ $$$$\int\:\frac{\mathrm{sin}\:{x}\:\mathrm{cos}\:{x}}{\mathrm{sin}\:{x}\:+\:\mathrm{cos}\:{x}}\:{dx}\:=\:…

let-F-x-1-x-1-5-2x-3-4-1-find-F-x-dx-2-en-deduire-la-decomposition-de-F-en-element-simples-

Question Number 147683 by mathmax by abdo last updated on 22/Jul/21 $$\mathrm{let}\:\mathrm{F}\left(\mathrm{x}\right)=\frac{\mathrm{1}}{\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{5}} \left(\mathrm{2x}−\mathrm{3}\right)^{\mathrm{4}} } \\ $$$$\left.\mathrm{1}\right)\:\mathrm{find}\:\int\:\mathrm{F}\left(\mathrm{x}\right)\mathrm{dx} \\ $$$$\left.\mathrm{2}\right)\mathrm{en}\:\mathrm{deduire}\:\mathrm{la}\:\mathrm{decomposition}\:\mathrm{de}\:\mathrm{F}\:\mathrm{en}\:\mathrm{element}\:\mathrm{simples} \\ $$ Answered by mathmax by abdo…

decompose-F-x-1-x-n-1-x-2-x-1-dans-C-x-puis-dans-R-x-

Question Number 147682 by mathmax by abdo last updated on 22/Jul/21 $$\mathrm{decompose}\:\mathrm{F}\left(\mathrm{x}\right)=\frac{\mathrm{1}}{\left(\mathrm{x}^{\mathrm{n}} −\mathrm{1}\right)\left(\mathrm{x}^{\mathrm{2}} \:+\mathrm{x}+\mathrm{1}\right)}\:\mathrm{dans}\:\mathrm{C}\left(\mathrm{x}\right)\:\mathrm{puis}\:\mathrm{dans}\:\mathrm{R}\left(\mathrm{x}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question-147670

Question Number 147670 by mnjuly1970 last updated on 22/Jul/21 Answered by Olaf_Thorendsen last updated on 22/Jul/21 $$\mathrm{By}\:\mathrm{definition}\:\mathrm{H}_{{n}} ^{\left(\mathrm{2}\right)} \:=\:\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{\mathrm{1}}{{k}^{\mathrm{2}} } \\ $$$$\Rightarrow\:\mathrm{H}_{{n}−\mathrm{1}} ^{\left(\mathrm{2}\right)}…