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Category: Integration

3-dx-x-3-2-

Question Number 14287 by tawa tawa last updated on 30/May/17 $$\int_{\:\:\mathrm{3}} ^{\:\:\infty} \:\:\frac{\mathrm{dx}}{\left(\mathrm{x}\:−\:\mathrm{3}\right)^{\mathrm{2}} } \\ $$ Commented by prakash jain last updated on 30/May/17 $$\mathrm{No}\:\mathrm{answer}\:\mathrm{integral}\:\mathrm{does}\:\mathrm{not}…

Evaluate-0-1-ln-1-x-2-arctan-x-dx-

Question Number 145358 by qaz last updated on 04/Jul/21 $$\mathrm{Evaluate}::\:\:\:\int_{\mathrm{0}} ^{\mathrm{1}} \mathrm{ln}\left(\mathrm{1}+\mathrm{x}^{\mathrm{2}} \right)\centerdot\mathrm{arctan}\left(\mathrm{x}\right)\mathrm{dx}=? \\ $$ Answered by Olaf_Thorendsen last updated on 04/Jul/21 $$\mathrm{I}\:=\:\int_{\mathrm{0}} ^{\mathrm{1}} \mathrm{ln}\left(\mathrm{1}+{x}^{\mathrm{2}}…

Question-14284

Question Number 14284 by tawa tawa last updated on 30/May/17 Answered by Tinkutara last updated on 30/May/17 $$\int_{\frac{−\mathrm{3}}{\mathrm{2}}} ^{\infty} \frac{{dx}}{\mathrm{4}{x}^{\mathrm{2}} \:+\:\mathrm{12}{x}\:+\:\mathrm{13}}\:=\:\frac{\mathrm{1}}{\mathrm{4}}\int_{\frac{−\mathrm{3}}{\mathrm{2}}} ^{\infty} \frac{{dx}}{{x}^{\mathrm{2}} \:+\:\mathrm{3}{x}\:+\:\frac{\mathrm{13}}{\mathrm{4}}} \\…

n-1-1-n-n-2n-1-

Question Number 145345 by qaz last updated on 04/Jul/21 $$\underset{\mathrm{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{\mathrm{n}} \mathrm{n}}{\left(\mathrm{2n}+\mathrm{1}\right)!}=? \\ $$ Answered by Olaf_Thorendsen last updated on 04/Jul/21 $$\mathrm{sin}{x}\:=\:\underset{{n}=\mathrm{0}} {\overset{{n}} {\sum}}\left(−\mathrm{1}\right)^{{n}}…

Question-14274

Question Number 14274 by christine last updated on 30/May/17 Answered by Tinkutara last updated on 30/May/17 $$\int_{\mathrm{1}} ^{\infty} \frac{{xdx}}{{x}\:+\:\mathrm{1}}\:=\:\int_{\mathrm{1}} ^{\infty} \left(\mathrm{1}\:−\:\frac{\mathrm{1}}{{x}\:+\:\mathrm{1}}\right){dx} \\ $$$$=\:\int_{\mathrm{1}} ^{\infty} {dx}\:−\:\int_{\mathrm{1}}…

Calculus-n-0-1-n-n-1-

Question Number 145319 by mnjuly1970 last updated on 04/Jul/21 $$\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:#\:\:\mathrm{Calculus}# \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\:\frac{\mathrm{1}}{{n}!\:+\:\left({n}\:+\:\mathrm{1}\:\right)!}\:=? \\ $$$$ \\ $$ Answered by Dwaipayan Shikari last…