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Category: Integration

S-x-n-1-2n-2n-1-x-2n-x-lt-1-

Question Number 144924 by qaz last updated on 30/Jun/21 $$\mathrm{S}\left(\mathrm{x}\right)=\underset{\mathrm{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\left(\mathrm{2n}\right)!!}{\left(\mathrm{2n}+\mathrm{1}\right)!!}\mathrm{x}^{\mathrm{2n}} =?……..\left(\mid\mathrm{x}\mid<\mathrm{1}\right) \\ $$ Answered by Ar Brandon last updated on 30/Jun/21 $$\left(\mathrm{2n}+\mathrm{1}\right)!!=\frac{\left(\mathrm{2n}+\mathrm{1}\right)!}{\left(\mathrm{2n}\right)!!} \\…

dx-1-cos-x-

Question Number 79352 by M±th+et£s last updated on 24/Jan/20 $$\int\frac{{dx}}{\mathrm{1}−\sqrt{{cos}\left({x}\right)}} \\ $$ Commented by mr W last updated on 24/Jan/20 $${no}\:{solution}\:{with}\:{elementary}\:{functions}. \\ $$$${or}\:{do}\:{you}\:{know}\:{a}\:{solution}? \\ $$…

0-1-1-sin-x-1-x-dx-ln-2tan-1-2-

Question Number 144876 by qaz last updated on 30/Jun/21 $$\:\:\:\:\:\:\:\:\:\:\int_{\mathrm{0}} ^{\mathrm{1}} \left(\frac{\mathrm{1}}{\mathrm{sin}\:\mathrm{x}}−\frac{\mathrm{1}}{\mathrm{x}}\right)\mathrm{dx}=\mathrm{ln}\left(\mathrm{2tan}\:\frac{\mathrm{1}}{\mathrm{2}}\right) \\ $$ Answered by mindispower last updated on 30/Jun/21 $$ \\ $$$${sin}\left({x}\right)=\frac{\mathrm{2}{tg}\left(\frac{{x}}{\mathrm{2}}\right)}{\mathrm{1}+{tg}^{\mathrm{2}} \left(\frac{{x}}{\mathrm{2}}\right)}…

Convergence-of-1-I-1-e-t-5-sin-lnt-t-1-3-2-dt-2-I-1-lnx-x-1-x-dx-

Question Number 79325 by Henri Boucatchou last updated on 24/Jan/20 $$\:\boldsymbol{{Convergence}}\:\:\boldsymbol{{of}}\:: \\ $$$$\left.\:\:\mathrm{1}\right)\:\:\:\boldsymbol{{I}}=\int_{\mathrm{1}} ^{\:\infty} \frac{\boldsymbol{{e}}^{−\boldsymbol{{t}}/\mathrm{5}} \mid\boldsymbol{{sin}}\left(\boldsymbol{{lnt}}\right)\mid}{\left(\boldsymbol{{t}}−\mathrm{1}\right)^{\mathrm{3}/\mathrm{2}} }\boldsymbol{{dt}} \\ $$$$\left.\:\:\mathrm{2}\right)\:\:\:\boldsymbol{{I}}=\int_{\mathrm{1}} ^{\infty} \frac{\sqrt{\boldsymbol{{lnx}}}}{\left(\boldsymbol{{x}}−\mathrm{1}\right)\sqrt{\boldsymbol{{x}}}}\boldsymbol{{dx}} \\ $$ Commented by…

I-0-1-ln-x-1-x-2-dx-0-1-ln-x-n-0-1-n-x-2n-dx-n-0-1-n-0-1-x-2n-ln-x-dx-n-0-

Question Number 144813 by mnjuly1970 last updated on 29/Jun/21 $$ \\ $$$$\:\:\:\:\:\:\mathrm{I}:=\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{\mathrm{ln}\:\left({x}\right)}{\mathrm{1}\:+\:{x}^{\:\mathrm{2}} }\:{dx} \\ $$$$\:\:\:\:\:\:\:\:\::=\:\int_{\mathrm{0}} ^{\:\mathrm{1}} \mathrm{ln}\left({x}\:\right)\:\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\left(−\mathrm{1}\right)^{\:{n}} \:{x}^{\:\mathrm{2}{n}} \:{dx} \\ $$$$\:\:\:\:\:\:\:\::=\:\underset{{n}=\mathrm{0}}…

Question-144815

Question Number 144815 by mnjuly1970 last updated on 29/Jun/21 Answered by mindispower last updated on 30/Jun/21 $$=\int_{\mathrm{0}} ^{\infty} \frac{{sin}\left({x}+\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }\right)+{sin}\left(\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }−{x}\right)}{\mathrm{2}\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }\:}{dx} \\ $$$${x}={sh}\left({t}\right) \\…