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Category: Integration

log-x-2-dx-

Question Number 15235 by arnabpapu550@gmail.com last updated on 08/Jun/17 (logx)2dx=? Answered by liday last updated on 18/Jun/17 $$\int\left({log}\sqrt{{x}}\right)^{\mathrm{2}} {dx}=\frac{\mathrm{1}}{\mathrm{4}}\int\left({logx}\right)^{\mathrm{2}} {dx}=\frac{\mathrm{1}}{\mathrm{4}}\left[{x}\left({logx}\right)^{\mathrm{2}} −\int{x}\centerdot\mathrm{2}{logx}\centerdot\frac{\mathrm{1}}{{x}}{dx}\right] \

K-1-1-x-3-dx-

Question Number 146212 by puissant last updated on 12/Jul/21 K=11+x3dx Answered by Ar Brandon last updated on 12/Jul/21 $$\mathrm{I}=\int\frac{\mathrm{dx}}{\:\sqrt{\mathrm{1}+\mathrm{x}^{\mathrm{3}} }}=\int\frac{\mathrm{dx}}{\:\sqrt{\mathrm{1}+\left(\mathrm{x}^{\mathrm{3}/\mathrm{2}} \right)^{\mathrm{2}} }},\:\mathrm{u}=\mathrm{x}^{\mathrm{3}/\mathrm{2}}…