Question Number 128954 by mathmax by abdo last updated on 11/Jan/21 $$\mathrm{calculate}\:\:\mathrm{f}\left(\lambda\right)\:=\int_{\mathrm{0}} ^{\mathrm{1}} \mathrm{ln}\left(\mathrm{x}^{\mathrm{4}} \:+\lambda^{\mathrm{4}} \right)\mathrm{dx}\:\:\:\mathrm{with}\:\lambda>\mathrm{0}\:\mathrm{then}\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of} \\ $$$$\int_{\mathrm{0}} ^{\mathrm{1}} \mathrm{ln}\left(\mathrm{1}+\mathrm{x}^{\mathrm{4}} \right)\mathrm{dx} \\ $$ Answered by…
Question Number 128952 by mathmax by abdo last updated on 11/Jan/21 $$\mathrm{calculate}\:\mathrm{A}_{\mathrm{n}} =\int_{\mathrm{0}} ^{\infty} \:\:\frac{\mathrm{dx}}{\left(\mathrm{x}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{n}} }\:\:\:,\:\mathrm{n}\:\mathrm{integr}\:\mathrm{and}\:\mathrm{n}\geqslant\mathrm{1} \\ $$ Answered by Dwaipayan Shikari last updated…
Question Number 128950 by mathmax by abdo last updated on 11/Jan/21 $$\mathrm{calculate}\:\mathrm{f}\left(\mathrm{a}\right)\:=\int_{\mathrm{0}} ^{\infty} \:\:\frac{\mathrm{dx}}{\left(\mathrm{x}^{\mathrm{2}} +\mathrm{a}\right)^{\mathrm{2}} \left(\mathrm{x}^{\mathrm{2}} −\mathrm{x}+\mathrm{1}\right)^{\mathrm{2}} }\:\:\mathrm{with}\:\mathrm{a}>\mathrm{0} \\ $$ Terms of Service Privacy Policy…
Question Number 128953 by mathmax by abdo last updated on 11/Jan/21 $$\mathrm{calculate}\:\int_{\mathrm{0}} ^{\mathrm{1}} \mathrm{ln}\left(\mathrm{1}+\mathrm{x}^{\mathrm{6}} \right)\mathrm{dx} \\ $$ Answered by Lordose last updated on 12/Jan/21 $$…
Question Number 63410 by aliesam last updated on 03/Jul/19 Commented by mathmax by abdo last updated on 03/Jul/19 $$\left.\mathrm{2}\right)\:{let}\:{I}\:=\int\:\:\:\frac{{xdx}}{\mathrm{1}+{sinx}}\:\:\:{changement}\:{tan}\left(\frac{{x}}{\mathrm{2}}\right)={t}\:{give}\: \\ $$$${I}\:=\:\int\:\:\:\frac{\mathrm{2}{arctan}\left({t}\right)}{\left(\mathrm{1}+\frac{\mathrm{2}{t}}{\mathrm{1}+{t}^{\mathrm{2}} }\right)\left(\mathrm{1}+{t}^{\mathrm{2}} \right)}{dt}\:=\:\mathrm{2}\int\:\:\:\:\frac{{arctan}\left({t}\right)}{\mathrm{1}+{t}^{\mathrm{2}} \:+\mathrm{2}{t}}\:{dt}\:=\mathrm{2}\:\int\:\:\:\frac{{arctan}\left({t}\right)}{\left({t}+\mathrm{1}\right)^{\mathrm{2}} }\:{dt}\:\:…
Question Number 128943 by bramlexs22 last updated on 11/Jan/21 $$\:\int\:\frac{\mathrm{x}^{\mathrm{9}} }{\left(\mathrm{x}^{\mathrm{2}} +\mathrm{m}^{\mathrm{2}} \right)\mathrm{sec}\:\left(\mathrm{5x}\right)}\:\mathrm{dx}\:? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 63405 by mathmax by abdo last updated on 03/Jul/19 $${find}\:\int\:\sqrt{\frac{{x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{1}}{{x}+\mathrm{2}}}{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 63404 by mathmax by abdo last updated on 03/Jul/19 $$\left.\mathrm{1}\right)\:{find}\:\:\int\:\:\:\:\frac{{x}+\mathrm{1}}{{x}^{\mathrm{3}} −\mathrm{3}{x}\:−\mathrm{2}}{dx} \\ $$$$\left.\mathrm{2}\right)\:{calculate}\:\:\int_{\mathrm{4}} ^{+\infty} \:\:\:\:\:\frac{{x}+\mathrm{1}}{{x}^{\mathrm{3}} −\mathrm{3}{x}\:+\mathrm{2}}{dx} \\ $$ Commented by MJS last updated…
Question Number 63395 by mathmax by abdo last updated on 03/Jul/19 $${let}\:{f}\left({t}\right)\:=\int_{\mathrm{0}} ^{\infty} \:\frac{{ln}\left(\mathrm{1}+{tx}\right)}{\mathrm{1}+{x}^{\mathrm{2}} }{dx}\:\:\:{with}\:\:\mid{t}\mid<\mathrm{1} \\ $$$$\left.\mathrm{1}\right)\:{determine}\:{a}\:{explicit}\:\:{form}\:{of}\:{f}\left({t}\right) \\ $$$$\left.\mathrm{2}\right)\:{find}\:{the}\:{value}\:{of}\:\int_{\mathrm{0}} ^{\infty} \:\:\:\frac{{ln}\left(\mathrm{1}+{x}\right)}{\mathrm{1}+{x}^{\mathrm{2}} }{dx} \\ $$ Commented…
Question Number 128926 by liberty last updated on 11/Jan/21 $$\:\beta\:=\:\int_{\mathrm{0}} ^{\:\mathrm{5}} \:\frac{{dx}}{{x}^{\mathrm{3}} \left(\mathrm{1}+{e}^{{x}} \right)^{\mathrm{2}} }\:? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com