Question Number 144528 by imjagoll last updated on 26/Jun/21 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{volume}\:\mathrm{of}\:\mathrm{the}\:\mathrm{region}\: \\ $$$$\mathrm{bounded}\:\mathrm{by}\:\mathrm{the}\:\mathrm{elliptic}\:\mathrm{paraboloid} \\ $$$$\mathrm{z}\:=\:\mathrm{4}−\mathrm{x}^{\mathrm{2}} −\frac{\mathrm{1}}{\mathrm{4}}\mathrm{y}^{\mathrm{2}} \:\mathrm{and}\:\mathrm{the}\:\mathrm{plane}\:\mathrm{z}=\mathrm{0} \\ $$$$ \\ $$ Answered by EDWIN88 last updated…
Question Number 144527 by mnjuly1970 last updated on 26/Jun/21 $$ \\ $$$$\:\:\:\:\:\:\:\:\:\:…..\:\:\:\mathrm{Calculus}\:\:\left(\mathrm{I}\:\right)….. \\ $$$$\mathrm{P}:=\:\frac{\int_{\mathrm{0}\:} ^{\:\:\frac{\pi}{\mathrm{2}}} \left(\:{xcos}\left({x}\right)+\mathrm{1}\:\right){e}^{\:{sin}\left({x}\right)} {dx}\:}{\int_{\mathrm{0}} ^{\:\frac{\pi}{\mathrm{2}}} \left(\:{xsin}\left({x}\right)\:−\mathrm{1}\:\right){e}^{\:{cos}\left({x}\:\right)} {dx}}=? \\ $$ Answered by Kamel…
Question Number 144450 by mnjuly1970 last updated on 25/Jun/21 $$ \\ $$$$\:\:\:\:\:\:\:\:………\mathrm{C}{alculus}\left(\mathrm{I}\right)……… \\ $$$$\:\:\mathrm{Lim}_{\:\:{x}\:\rightarrow\:\mathrm{0}} \frac{\mathrm{1}\:−{cos}\left({xcos}\left(\frac{{x}}{\mathrm{2}}\right).{cos}\left(\frac{{x}}{\mathrm{4}}\right){cos}\left(\frac{{x}}{\mathrm{8}}\right)\right)}{{x}^{\:\mathrm{2}} }=? \\ $$ Answered by Dwaipayan Shikari last updated on…
Question Number 13365 by tawa tawa last updated on 19/May/17 $$\int\:\:\mathrm{e}^{\left(\mathrm{x}\:+\:\mathrm{e}^{\mathrm{x}} \right)} \:\:\mathrm{dx} \\ $$ Answered by b.e.h.i.8.3.4.1.7@gmail.com last updated on 19/May/17 Commented by tawa…
Question Number 144432 by ArielVyny last updated on 25/Jun/21 $$\int_{\mathrm{0}} ^{\propto} {t}^{{n}−\mathrm{2}} {costdt} \\ $$ Answered by Dwaipayan Shikari last updated on 25/Jun/21 $$\int_{\mathrm{0}} ^{\infty}…
Question Number 13364 by tawa tawa last updated on 19/May/17 $$\int_{\:\:\:\mathrm{0}} ^{\:\:\frac{\mathrm{3}\sqrt{\mathrm{3}}}{\mathrm{2}}} \:\:\:\frac{\mathrm{x}^{\mathrm{3}} }{\:\sqrt{\mathrm{4x}^{\mathrm{2}} \:−\:\mathrm{9}}}\:\:\mathrm{dx} \\ $$ Commented by b.e.h.i.8.3.4.1.7@gmail.com last updated on 19/May/17 $${you}\:{should}\:{change}\:{the}\:{limits}\:{of}\:{integral}.…
Question Number 78897 by Mikael_786 last updated on 21/Jan/20 Commented by mind is power last updated on 21/Jan/20 $${translate}\:{please} \\ $$ Commented by mr W…
Question Number 13362 by tawa tawa last updated on 19/May/17 $$\int\:\frac{\mathrm{x}^{\mathrm{3}} }{\:\sqrt{\mathrm{16}\:−\:\mathrm{x}^{\mathrm{2}} }}\:\:\mathrm{dx} \\ $$ Answered by ajfour last updated on 19/May/17 $${I}=\frac{\mathrm{1}}{\mathrm{2}}\int\:\frac{{x}^{\mathrm{2}} \left(\mathrm{2}{xdx}\right)}{\:\sqrt{\mathrm{16}−{x}^{\mathrm{2}} }}…
Question Number 13360 by tawa tawa last updated on 19/May/17 $$\int\:\:\frac{\mathrm{x}}{\:\sqrt{\mathrm{3}\:−\:\mathrm{2x}\:−\:\mathrm{x}^{\mathrm{2}} }}\:\mathrm{dx} \\ $$ Answered by ajfour last updated on 19/May/17 $$\boldsymbol{{I}}=\int\frac{\mathrm{x}+\mathrm{1}−\mathrm{1}}{\:\sqrt{\mathrm{4}−\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{2}} }}\:\mathrm{dx} \\ $$$$−\frac{\mathrm{1}}{\mathrm{2}}\int\frac{−\mathrm{2}\left({x}+\mathrm{1}\right)}{\:\sqrt{\mathrm{4}−\left({x}+\mathrm{1}\right)^{\mathrm{2}}…
Question Number 144431 by imjagoll last updated on 25/Jun/21 $$\:\:\:\int\mathrm{tan}\:\mathrm{x}\:\mathrm{sin}\:^{\mathrm{2}} \mathrm{x}\:\mathrm{cos}\:^{\mathrm{3}} \mathrm{x}\:\mathrm{cot}\:^{\mathrm{4}} \mathrm{x}\:\mathrm{dx}\:=? \\ $$ Answered by iloveisrael last updated on 25/Jun/21 $$\:\int\:\frac{\mathrm{cos}\:^{\mathrm{6}} \mathrm{x}\:\mathrm{sin}\:\mathrm{x}}{\mathrm{sin}\:^{\mathrm{2}} \mathrm{x}}\:\mathrm{dx}\:=\:\int\:\frac{\mathrm{cos}\:^{\mathrm{6}}…