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Category: Integration

Question-78549

Question Number 78549 by aliesam last updated on 18/Jan/20 Answered by ~blr237~ last updated on 18/Jan/20 $$\mathrm{let}\:\mathrm{named}\:\mathrm{it}\:\mathrm{A} \\ $$$$\mathrm{state}\:\mathrm{u}=\frac{\mathrm{x}}{\mathrm{2}}\:\:,\:\mathrm{A}=\mathrm{2}\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \frac{\sqrt{\mathrm{tan2u}}}{\mathrm{1}+\mathrm{sinu}}\:\mathrm{du} \\ $$$$\frac{\mathrm{A}}{\mathrm{2}}=\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \frac{\sqrt{\mathrm{tan2u}}}{\mathrm{cos}^{\mathrm{2}}…

sin-4-x-cos-3-x-dx-

Question Number 13000 by Joel577 last updated on 10/May/17 $$\int\:\mathrm{sin}^{\mathrm{4}} \:{x}\:\mathrm{cos}^{\mathrm{3}} \:{x}\:{dx} \\ $$ Commented by Joel577 last updated on 10/May/17 $$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{idea}\:\mathrm{to}\:\mathrm{solve}\:\mathrm{that}\:\mathrm{problem}? \\ $$ Commented…

Question-144064

Question Number 144064 by 0731619 last updated on 21/Jun/21 Answered by MJS_new last updated on 21/Jun/21 $$\mathrm{simply}\:\mathrm{let}\:{t}=\mathrm{tan}\:{x} \\ $$$$\Rightarrow\:\mathrm{answer}\:\mathrm{is} \\ $$$$−\frac{{x}}{{b}^{\mathrm{2}} }+\frac{\sqrt{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} }}{{ab}^{\mathrm{2}} }\mathrm{arctan}\:\frac{{a}\mathrm{tan}\:{x}}{\:\sqrt{{a}^{\mathrm{2}}…

Calculus-lim-1-pi-0-2pi-k-1-n-sin-kx-2-k-2-dx-

Question Number 144053 by mnjuly1970 last updated on 21/Jun/21 $$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:……..\:{Calculus}…….. \\ $$$$\:\:\:\:\:\:\:\Omega:={lim}\frac{\mathrm{1}}{\pi}\int_{\mathrm{0}} ^{\:\mathrm{2}\pi} \left(\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{{sin}\left({kx}\right)}{\:\sqrt{\mathrm{2}^{{k}} }}\right)^{\mathrm{2}} {dx}=? \\ $$$$ \\ $$ Answered…

Question-144042

Question Number 144042 by maryxxxx last updated on 20/Jun/21 Answered by mindispower last updated on 20/Jun/21 $$\int\frac{{dx}}{{x}^{\mathrm{3}} \sqrt{\mathrm{1}−\left(\frac{\mathrm{10}}{{x}}\right)^{\mathrm{2}} }} \\ $$$${y}=\frac{\mathrm{100}}{{x}^{\mathrm{2}} },{y}<\mathrm{1}\Rightarrow{dy}=\frac{−\mathrm{200}}{{x}^{\mathrm{3}} }{dx} \\ $$$$\Rightarrow\frac{−\mathrm{1}}{\mathrm{200}}\int\frac{{dy}}{\:\sqrt{\mathrm{1}−{y}}}{dy}=\frac{\mathrm{1}}{\mathrm{100}}\sqrt{\mathrm{1}−{y}}+{c}=\frac{\sqrt{\mathrm{1}−\frac{\mathrm{100}}{{x}^{\mathrm{2}}…