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Category: Integration

let-I-0-pi-x-cos-4-x-dxand-J-0-pi-x-sin-4-xdx-1-calculate-I-J-and-I-J-2-find-the-values-of-I-and-J-

Question Number 78264 by msup trace by abdo last updated on 15/Jan/20 $${let}\:{I}\:=\int_{\mathrm{0}} ^{\pi} {x}\:{cos}^{\mathrm{4}} {x}\:{dxand}\:{J}=\int_{\mathrm{0}} ^{\pi} {x}\:{sin}^{\mathrm{4}} {xdx} \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:{I}+{J}\:{and}\:{I}−{J} \\ $$$$\left.\mathrm{2}\right)\:{find}\:{the}\:{values}\:{of}\:{I}\:{and}\:{J} \\ $$…

x-4-x-x-1-3-dx-

Question Number 78251 by aliesam last updated on 15/Jan/20 $$\int\frac{{x}+\mathrm{4}}{{x}−\sqrt[{\mathrm{3}}]{{x}}}\:{dx}\: \\ $$ Answered by john santu last updated on 15/Jan/20 $${let}\:{x}\:=\:{u}^{\mathrm{3}} \:\Rightarrow{dx}=\mathrm{3}{u}^{\mathrm{2}} \:{du} \\ $$$$\int\:\frac{{u}^{\mathrm{3}}…

find-cos-2-2x-dx-

Question Number 12702 by mad last updated on 29/Apr/17 $${find}\:\int{cos}^{\mathrm{2}} \mathrm{2}{x}\:{dx} \\ $$ Answered by Joel577 last updated on 29/Apr/17 $$\mathrm{cos}^{\mathrm{2}} \:\mathrm{2}{x}\:=\:\frac{\mathrm{1}\:+\:\mathrm{cos}\:\mathrm{4}{x}}{\mathrm{2}} \\ $$$$\int\:\mathrm{cos}^{\mathrm{2}} \:\mathrm{2}{x}\:{dx}…