Question Number 64106 by mmkkmm000m last updated on 13/Jul/19 $$\int{tan}\left(\mathrm{1}/{x}\right){dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 64105 by mmkkmm000m last updated on 13/Jul/19 $$\int{tan}\left(\mathrm{1}/{x}\right){dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 64103 by mmkkmm000m last updated on 13/Jul/19 $$\int{tan}\left(\mathrm{1}/{x}\right){dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 64104 by mmkkmm000m last updated on 13/Jul/19 $$\int{tan}\left(\mathrm{1}/{x}\right){dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 64102 by mmkkmm000m last updated on 13/Jul/19 $$\int{tan}\left(\mathrm{1}/{x}\right){dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 129635 by pticantor last updated on 17/Jan/21 $$\:\:\:\:\: \\ $$$$ \\ $$$$\:\:\:\:\:\:\int\frac{\boldsymbol{{dx}}}{\left(\boldsymbol{{x}}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{2}} }=? \\ $$$$\underset{\boldsymbol{{k}}=\mathrm{1}} {\overset{\boldsymbol{{n}}} {\sum}}\frac{\mathrm{1}}{\boldsymbol{{k}}\left(\boldsymbol{{k}}+\mathrm{1}\right)\left(\mathrm{2}\boldsymbol{{k}}+\mathrm{1}\right)}=? \\ $$ Commented by liberty…
Question Number 64068 by mathmax by abdo last updated on 12/Jul/19 $${calculate}\:\int_{\mathrm{0}} ^{\pi} \:\frac{{tsint}}{\mathrm{3}+{sin}^{\mathrm{2}} {t}}\:{dt}\: \\ $$ Commented by mathmax by abdo last updated on…
Question Number 64065 by mathmax by abdo last updated on 12/Jul/19 $${calculate}\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\frac{{ln}\left(\mathrm{1}+{x}\right)}{\mathrm{1}+{x}^{\mathrm{2}} }{dx} \\ $$ Commented by mathmax by abdo last updated on…
Question Number 129594 by bagjagunawan last updated on 16/Jan/21 Commented by bemath last updated on 17/Jan/21 $$\:\mathrm{sin}\:\mathrm{x}+\mathrm{cos}\:\mathrm{x}+\frac{\mathrm{1}+\mathrm{sin}\:\mathrm{x}+\mathrm{cos}\:\mathrm{x}}{\mathrm{cos}\:\mathrm{x}\:\mathrm{sin}\:\mathrm{x}}\:=\: \\ $$$$\:\mathrm{sin}\:\mathrm{x}+\mathrm{cos}\:\mathrm{x}\:+\frac{\mathrm{2cos}\:\left(\frac{\mathrm{x}}{\mathrm{2}}\right)\left(\mathrm{sin}\:\left(\frac{\mathrm{x}}{\mathrm{2}}\right)+\mathrm{cos}\:\left(\frac{\mathrm{x}}{\mathrm{2}}\right)\right)}{\mathrm{2sin}\:\left(\frac{\mathrm{x}}{\mathrm{2}}\right)\mathrm{cos}\:\left(\frac{\mathrm{x}}{\mathrm{2}}\right)\mathrm{cos}\:\mathrm{x}}\:= \\ $$$$\:\mathrm{sin}\:\mathrm{x}+\mathrm{cos}\:\mathrm{x}+\frac{\mathrm{1}}{\mathrm{sin}\:\left(\frac{\mathrm{x}}{\mathrm{2}}\right)\left(\mathrm{cos}\:\left(\frac{\mathrm{x}}{\mathrm{2}}\right)−\mathrm{sin}\:\left(\frac{\mathrm{x}}{\mathrm{2}}\right)\right)}= \\ $$$$\:\mathrm{sin}\:\mathrm{x}+\mathrm{cos}\:\mathrm{x}\:+\:\frac{\mathrm{2}}{\mathrm{sin}\:\mathrm{x}−\mathrm{1}+\mathrm{cos}\:\mathrm{x}}= \\ $$$$\:\mathrm{sin}\:\mathrm{x}+\mathrm{cos}\:\mathrm{x}+\:\frac{\mathrm{2}}{\mathrm{sin}\:\mathrm{x}+\mathrm{cos}\:\mathrm{x}−\mathrm{1}}=\frac{\left(\mathrm{sin}\:\mathrm{x}+\mathrm{cos}\:\mathrm{x}\right)^{\mathrm{2}}…
Question Number 129576 by greg_ed last updated on 16/Jan/21 $$\boldsymbol{\mathrm{please}},\:\boldsymbol{\mathrm{how}}\:\boldsymbol{\mathrm{to}}\:\boldsymbol{\mathrm{show}}\:\boldsymbol{\mathrm{that}}\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\boldsymbol{{f}}\::\:\left[\mathrm{0}\:,\:\boldsymbol{{a}}\right]\:×\:\mathbb{R}_{+} \:\rightarrow\:\mathbb{R} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\boldsymbol{{x}},\:\boldsymbol{{y}}\right)\:\:\:\:\:\:\: \:\:\boldsymbol{{e}}^{−\boldsymbol{{xy}}} \:\boldsymbol{{sin}}\:\boldsymbol{{x}}\: \\ $$$$\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{integrable}}\:???\: \\ $$ Answered by mathmax by…