Category: Integration

Question Number 143142 by Ar Brandon last updated on 10/Jun/21 $$\int \frac{{\mathrm{x}}^2-1}{{\mathrm{x}}^2+1}\cdot \frac{1}{\sqrt{1+{\mathrm{x}}^4}}\mathrm{dx}$$ Answered by Olaf_Thorendsen last updated on 10/Jun/21 $$\mathrm{F}\left({x}\right)\:=\:\int\frac{{x}^{\mathrm{2}} −\mathrm{1}}{{x}^{\mathrm{2}}…

Question Number 77593 by BK last updated on 08/Jan/20 Commented by $@ty@m123lastupdatedon08/Jan/20$$Therepeatationofthisquestion$$$\$issufficienttoprovethatMr.BK$$$$isnoneotherthan\dots$$ Commented by…

Question Number 77570 by TawaTawa last updated on 08/Jan/20 $${\int }_0^1\log \left(\frac{1+\mathrm{x}+{\mathrm{x}}^2+{\mathrm{x}}^3+{\mathrm{x}}^4}{\sqrt{1+\frac{1}{\mathrm{x}}+\frac{1}{{\mathrm{x}}^2}+\frac{1}{{\mathrm{x}}^3}+\frac{1}{{\mathrm{x}}^4}}}\right)\mathrm{dx}$$ Answered by MJS last updated…

Question Number 143094 by bramlexs22 last updated on 10/Jun/21 Answered by liberty last updated on 10/Jun/21 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 143087 by bramlexs22 last updated on 10/Jun/21 Answered by Ar Brandon last updated on 10/Jun/21 $$\mathrm{x}=\sec \vartheta$$$$\mathrm{I}=\int_{\frac{\mathrm{2}\pi}{\mathrm{3}}} ^{\frac{\mathrm{5}\pi}{\mathrm{6}}} \frac{\mathrm{sec}\vartheta\mathrm{tan}\vartheta}{\mathrm{sec}\vartheta\sqrt{\mathrm{sec}^{\mathrm{2}} \vartheta−\mathrm{1}}}\mathrm{d}\vartheta=\int_{\frac{\mathrm{2}\pi}{\mathrm{3}}} ^{\frac{\mathrm{5}\pi}{\mathrm{6}}} \frac{\mathrm{tan}\vartheta}{\:\sqrt{\mathrm{tan}^{\mathrm{2}}…