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a-x-a-x-a-x-a-x-

Question Number 12130 by sujith last updated on 14/Apr/17 a+x/axax/a+x Answered by b.e.h.i.8.3.4.1.7@gmail.com last updated on 14/Apr/17 $$\frac{{a}+{x}}{{a}−{x}}={t}^{\mathrm{2}} \Rightarrow\frac{{a}+{x}−{a}+{x}}{{a}+{x}+{a}−{x}}=\frac{{t}^{\mathrm{2}} −\mathrm{1}}{{t}^{\mathrm{2}} +\mathrm{1}}\Rightarrow{x}={a}\frac{{t}^{\mathrm{2}}…