Category: Integration

Question Number 143094 by bramlexs22 last updated on 10/Jun/21 Answered by liberty last updated on 10/Jun/21 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 143087 by bramlexs22 last updated on 10/Jun/21 Answered by Ar Brandon last updated on 10/Jun/21 $$\mathrm{x}=\sec \vartheta$$$$\mathrm{I}=\int_{\frac{\mathrm{2}\pi}{\mathrm{3}}} ^{\frac{\mathrm{5}\pi}{\mathrm{6}}} \frac{\mathrm{sec}\vartheta\mathrm{tan}\vartheta}{\mathrm{sec}\vartheta\sqrt{\mathrm{sec}^{\mathrm{2}} \vartheta−\mathrm{1}}}\mathrm{d}\vartheta=\int_{\frac{\mathrm{2}\pi}{\mathrm{3}}} ^{\frac{\mathrm{5}\pi}{\mathrm{6}}} \frac{\mathrm{tan}\vartheta}{\:\sqrt{\mathrm{tan}^{\mathrm{2}}…

Question Number 143080 by Mathspace last updated on 09/Jun/21 $$calculate{\int }_0^{\mathrm{\infty }}\frac{arctan\left(x^2\right)}{1+x^2}dx$$ Answered by qaz last updated on 10/Jun/21 $$\int_{\mathrm{0}} ^{\infty}…

Question Number 143082 by Mathspace last updated on 09/Jun/21 $$calculatef(a,b)={\int }_0^{\mathrm{\infty }}\frac{e^{-{ax}^2}}{x^2+b^2}dx$$$$witha>0andb>0$$ Answered by Dwaipayan Shikari last…

Question Number 77536 by ~blr237~ last updated on 07/Jan/20 $$\mathrm{find}\mathrm{all}\mathrm{function}\mathrm{that}\mathrm{satisfy}$$$$\mathrm{\forall }\mathrm{p}>0{\int }_0^{\mathrm{\infty }}\mathrm{f}\left(\mathrm{t}\right){\mathrm{e}}^{-\mathrm{pt}}\mathrm{dt}={\mathrm{e}}^{-\mathrm{pT}}\mathrm{with}\mathrm{T}\mathrm{a}\mathrm{positive}\mathrm{real}$$ Answered by JDamian last updated on 07/Jan/20…