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Category: Integration

find-0-1-1-x-4-dx-

Question Number 75888 by abdomathmax last updated on 19/Dec/19 $${find}\:\int_{\mathrm{0}} ^{\mathrm{1}} \sqrt{\mathrm{1}+{x}^{\mathrm{4}} }{dx} \\ $$ Commented by 21042004 last updated on 20/Dec/19 $$\mathrm{this}\:\mathrm{equation}\:\mathrm{is}\:\mathrm{so}\:\mathrm{long} \\ $$$$\frac{\sqrt{\mathrm{2}}+\mathrm{2}\sqrt[{\mathrm{4}}]{−\mathrm{1}}\mathrm{F}\left(\mathrm{1}−\frac{{i}}{\mathrm{arcsinh}\left(\sqrt[{\mathrm{4}}]{−\mathrm{1}}\right)}\right)+\mathrm{2}\sqrt[{\mathrm{4}}]{−\mathrm{1}}{F}\left({i}\centerdot\mathrm{arcsinh}^{−\mathrm{1}}…

0-2-sin4x-1-sinx-cosx-dx-

Question Number 75848 by behi83417@gmail.com last updated on 18/Dec/19 $$\underset{\mathrm{0}} {\overset{\:\:\:\:\:\:\:\:\frac{\boldsymbol{\pi}}{\mathrm{2}}} {\int}}\frac{\boldsymbol{\mathrm{sin}}\mathrm{4}\boldsymbol{\mathrm{x}}}{\mathrm{1}+\boldsymbol{\mathrm{sinx}}+\boldsymbol{\mathrm{cosx}}}\boldsymbol{\mathrm{dx}}=? \\ $$ Commented by mathmax by abdo last updated on 18/Dec/19 $${let}\:{I}=\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}}…

Question-75838

Question Number 75838 by Crabby89p13 last updated on 18/Dec/19 Commented by MJS last updated on 19/Dec/19 $$\mathrm{testing}\:\mathrm{all}\:\mathrm{derivates} \\ $$$$\Rightarrow \\ $$$$\frac{{d}}{{dx}}\left[\frac{{x}^{\mathrm{12}} }{\mathrm{6}\left(\mathrm{2}{x}^{\mathrm{4}} +\mathrm{3}{x}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{3}} }\right]=…=\frac{\mathrm{3}{x}^{\mathrm{13}}…