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Category: Integration

Question-10188

Question Number 10188 by ridwan balatif last updated on 29/Jan/17 Commented by ridwan balatif last updated on 29/Jan/17 $$\int\sqrt{\mathrm{1}−\mathrm{tan}^{\mathrm{2}} \mathrm{2x}+\mathrm{tan}^{\mathrm{4}} \mathrm{2x}−\mathrm{tan}^{\mathrm{6}} \mathrm{2x}+…}\mathrm{dx}=…? \\ $$$$\mathrm{1}−\mathrm{tan}^{\mathrm{2}} \mathrm{2x}+\mathrm{tan}^{\mathrm{4}}…

I-0-x-a-2-b-2-x-2a-2-x-2-2b-2-dx-a-2-x-2-b-2-2-a-2-b-2-x-a-2-x-2-b-2-

Question Number 141244 by ajfour last updated on 17/May/21 $${I}=\int_{\mathrm{0}} ^{\:\infty} \frac{{x}\left\{\left({a}^{\mathrm{2}} −{b}^{\mathrm{2}} \right){x}−\mathrm{2}{a}^{\mathrm{2}} {x}^{\mathrm{2}} −\mathrm{2}{b}^{\mathrm{2}} \right\}{dx}}{\left({a}^{\mathrm{2}} {x}^{\mathrm{2}} +{b}^{\mathrm{2}} \right)^{\mathrm{2}} \left\{\left({a}^{\mathrm{2}} −{b}^{\mathrm{2}} \right){x}+{a}^{\mathrm{2}} {x}^{\mathrm{2}} +{b}^{\mathrm{2}}…

find-the-area-of-the-shaded-region-shown-below-which-is-boinded-by-to-functions-f-x-x-2-g-x-2-x-and-the-x-axis-

Question Number 141189 by Eric002 last updated on 16/May/21 $${find}\:{the}\:{area}\:{of}\:{the}\:{shaded}\:{region} \\ $$$${shown}\:{below}\:{which}\:{is}\:{boinded}\:{by}\:{to}\:{functions}\: \\ $$$${f}\left({x}\right)={x}^{\mathrm{2}} \:\:{g}\left({x}\right)=\mathrm{2}−{x}\:{and}\:{the}\:{x}-{axis} \\ $$$$ \\ $$ Commented by Eric002 last updated on…