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Category: Integration

find-0-1-1-x-4-dx-

Question Number 75888 by abdomathmax last updated on 19/Dec/19 $${find}\:\int_{\mathrm{0}} ^{\mathrm{1}} \sqrt{\mathrm{1}+{x}^{\mathrm{4}} }{dx} \\ $$ Commented by 21042004 last updated on 20/Dec/19 $$\mathrm{this}\:\mathrm{equation}\:\mathrm{is}\:\mathrm{so}\:\mathrm{long} \\ $$$$\frac{\sqrt{\mathrm{2}}+\mathrm{2}\sqrt[{\mathrm{4}}]{−\mathrm{1}}\mathrm{F}\left(\mathrm{1}−\frac{{i}}{\mathrm{arcsinh}\left(\sqrt[{\mathrm{4}}]{−\mathrm{1}}\right)}\right)+\mathrm{2}\sqrt[{\mathrm{4}}]{−\mathrm{1}}{F}\left({i}\centerdot\mathrm{arcsinh}^{−\mathrm{1}}…