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Category: Integration

dx-1-x-12-

Question Number 129645 by liberty last updated on 17/Jan/21 ϝ=dx1+x12. Answered by mathmax by abdo last updated on 17/Jan/21 $$\mathrm{roots}\:\mathrm{of}\:\mathrm{z}^{\mathrm{12}} +\mathrm{1}=\mathrm{0}\:\:\:\Rightarrow\mathrm{z}^{\mathrm{12}} \:=\mathrm{e}^{\mathrm{i}\pi\:+\mathrm{2ik}\pi}…