Question Number 9482 by sou1618 last updated on 10/Dec/16 $${find}\:\:{F}_{{n}} \left(−\mathrm{1}\right)\:{or}\:{F}_{{n}} \left({x}\right). \\ $$$${n}=\mathrm{1},\mathrm{2},\mathrm{3}…… \\ $$$${F}_{{n}} \left({x}\right)=\int\left(\mathrm{1}+{x}^{\mathrm{3}} \right)^{{n}} {dx} \\ $$ Commented by sou1618 last…
Question Number 9467 by tawakalitu last updated on 09/Dec/16 $$\int\mathrm{x}^{\mathrm{2}} \left(\sqrt{\mathrm{1}\:−\:\mathrm{x}^{\mathrm{2}} }\right)\:\mathrm{dx} \\ $$ Answered by mrW last updated on 09/Dec/16 $$\mathrm{x}=\mathrm{sin}\:\mathrm{t} \\ $$$$\mathrm{dx}=\mathrm{cos}\:\mathrm{t}\:\mathrm{dt} \\…
Question Number 74997 by chess1 last updated on 05/Dec/19 Commented by chess1 last updated on 05/Dec/19 $$\mathrm{answer}:\:\mathrm{A} \\ $$ Answered by mind is power last…
Question Number 74995 by vishalbhardwaj last updated on 05/Dec/19 $$\mathrm{find}\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \mathrm{Log}\:\mathrm{cos}{x}\:{dx} \\ $$ Commented by mathmax by abdo last updated on 06/Dec/19 $${let}\:{I}\:=\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}}…
Question Number 140500 by qaz last updated on 08/May/21 $$\mathrm{tan}\:^{\mathrm{2}} \mathrm{1}°+\mathrm{tan}\:^{\mathrm{2}} \mathrm{2}°+\mathrm{tan}\:^{\mathrm{2}} \mathrm{3}°+…+\mathrm{tan}\:^{\mathrm{2}} \mathrm{89}°=\frac{\mathrm{15931}}{\mathrm{3}}\:\:\:\:\:??? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 140490 by benjo_mathlover last updated on 08/May/21 Commented by john_santu last updated on 08/May/21 $$\frac{\pi}{\mathrm{2}}\:\left(\sqrt{\mathrm{2}\sqrt{\mathrm{2}}+\mathrm{2}}\:−\mathrm{2}\:\right)\:\approx\:\mathrm{0}.\mathrm{31} \\ $$ Answered by MJS_new last updated on…
Question Number 74944 by aliesam last updated on 04/Dec/19 $$\int\frac{{e}^{−{cos}\left(\mathrm{2}{x}\right)} }{{sin}^{\mathrm{2}} \left({x}\right)}\:{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 9381 by tawakalitu last updated on 03/Dec/16 $$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \:\mathrm{ln}\:\left(\frac{\mathrm{4}\:+\:\mathrm{3sinx}}{\mathrm{4}\:+\:\mathrm{3cosx}}\right)\:\mathrm{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 140447 by 676597498 last updated on 07/May/21 Answered by EDWIN88 last updated on 07/May/21 $$\mathrm{L}+\mathrm{M}=\underset{\mathrm{0}} {\overset{\pi/\mathrm{2}} {\int}}\mathrm{cos}\:^{\mathrm{2}} \mathrm{x}\:\mathrm{sin}\:^{\mathrm{2}} \mathrm{x}\left(\mathrm{cos}\:^{\mathrm{2}} \mathrm{x}+\mathrm{sin}\:^{\mathrm{2}} \mathrm{x}\right)\mathrm{dx} \\ $$$$\mathrm{L}+\mathrm{M}\:=\:\underset{\mathrm{0}}…
Question Number 74890 by abdomathmax last updated on 03/Dec/19 $${find}\:\int\:\:\:\left({x}+\mathrm{3}\right)\sqrt{\left({x}−\mathrm{1}\right)\left(\mathrm{2}−{x}\right)}{dx} \\ $$ Commented by mathmax by abdo last updated on 04/Dec/19 $${let}\:{I}\:=\int\:\left({x}+\mathrm{3}\right)\sqrt{\left({x}−\mathrm{1}\right)\left(\mathrm{2}−{x}\right)}{dx}\:\:{changement}\:\sqrt{{x}−\mathrm{1}}={t}\:{give} \\ $$$${x}−\mathrm{1}={t}^{\mathrm{2}} \:\Rightarrow{I}\:=\int\left({t}^{\mathrm{2}}…