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Category: Integration

Question-129594

Question Number 129594 by bagjagunawan last updated on 16/Jan/21 Commented by bemath last updated on 17/Jan/21 sinx+cosx+1+sinx+cosxcosxsinx=sinx+cosx+2cos(x2)(sin(x2)+cos(x2))2sin(x2)cos(x2)cosx=sinx+cosx+1sin(x2)(cos(x2)sin(x2))=sinx+cosx+2sinx1+cosx=$$\:\mathrm{sin}\:\mathrm{x}+\mathrm{cos}\:\mathrm{x}+\:\frac{\mathrm{2}}{\mathrm{sin}\:\mathrm{x}+\mathrm{cos}\:\mathrm{x}−\mathrm{1}}=\frac{\left(\mathrm{sin}\:\mathrm{x}+\mathrm{cos}\:\mathrm{x}\right)^{\mathrm{2}}…

reduction-formulas-for-n-N-some-n-gt-0-some-n-gt-1-sin-n-x-dx-1-n-cos-x-sin-n-1-x-n-1-n-sin-n-2-x-dx-cos-n-x-dx-1-n-sin-x-cos-n-1-x-n-1-n-cos-n-2-x-dx-tan-n-x-dx-1-

Question Number 64037 by MJS last updated on 18/Nov/19 reductionformulasfornN,somen>0,somen>1sinnxdx=1ncosxsinn1x+n1nsinn2xdxcosnxdx=1nsinxcosn1x+n1ncosn2xdx$$\int\mathrm{tan}^{{n}} \:{x}\:{dx}=\frac{\mathrm{1}}{{n}−\mathrm{1}}\mathrm{tan}^{{n}−\mathrm{1}}…

V-sin-x-sin-x-dx-

Question Number 129564 by bramlexs22 last updated on 16/Jan/21 V=sinxsin(x+θ)dx Answered by Lordose last updated on 16/Jan/21 Ω=sin(x)sin(x+θ)dx=u=x+θsin(uθ)sin(u)duΩ=sin(u)cosθcos(u)sinθsin(u)du=ucosθsinθln(sinu)+C$$\Omega\:=\:\left(\mathrm{x}+\theta\right)\mathrm{cos}\theta\:−\:\mathrm{sin}\theta\mathrm{ln}\left(\mathrm{sin}\left(\mathrm{x}+\theta\right)\right)+\:\mathrm{C}…