Question Number 7960 by tawakalitu last updated on 25/Sep/16 $$\int\frac{\mathrm{4}\:−\:{x}}{\mathrm{4}\:+\:{x}}\:{dx} \\ $$ Commented by Yozzia last updated on 25/Sep/16 $$\int\frac{\mathrm{4}−{x}}{\mathrm{4}+{x}}{dx}=\int\left(\frac{\mathrm{8}}{\mathrm{4}+{x}}−\mathrm{1}\right){dx}=\mathrm{8}{ln}\left({x}+\mathrm{4}\right)−{x}+{c} \\ $$ Commented by tawakalitu…
Question Number 7961 by tawakalitu last updated on 25/Sep/16 $$\int\frac{\mathrm{5}\:−\:{x}}{\mathrm{1}\:+\:\sqrt{{x}\:−\:\mathrm{4}}}\:{dx} \\ $$ Answered by Yozzia last updated on 25/Sep/16 $${I}=\int\frac{\mathrm{5}−{x}}{\mathrm{1}+\sqrt{{x}−\mathrm{4}}}{dx} \\ $$$${Let}\:{t}=\sqrt{{x}−\mathrm{4}}\Rightarrow{dt}=\frac{\mathrm{1}}{\mathrm{2}}\left({x}−\mathrm{4}\right)^{−\mathrm{1}/\mathrm{2}} {dx} \\ $$$${dx}=\mathrm{2}\left({x}−\mathrm{4}\right)^{\mathrm{1}/\mathrm{2}}…
Question Number 7959 by tawakalitu last updated on 25/Sep/16 $$\int\frac{{sin}^{−\mathrm{1}} \left({x}\right)}{\mathrm{1}\:−\:{x}^{\mathrm{2}} }\:{dx} \\ $$ Commented by nick last updated on 26/Sep/16 $${do}\:{you}\:{mean}\:\int\frac{\mathrm{sin}^{−\mathrm{1}} \left({x}\right)}{\:\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }}{dx} \\…
Question Number 7958 by tawakalitu last updated on 25/Sep/16 $$\int{cos}^{\mathrm{4}} {x}\:{sin}^{\mathrm{3}} {x}\:\:{dx}\: \\ $$ Commented by sandy_suhendra last updated on 25/Sep/16 $$=\int{cos}^{\mathrm{4}} {x}\:{sinx}\:{sin}^{\mathrm{2}} {x}\:{dx} \\…
Question Number 73489 by abdomathmax last updated on 13/Nov/19 $${calculate}\:\:\int_{\mathrm{0}} ^{\infty} \:\:\:\:\frac{{arctan}\left(\mathrm{3}+{x}^{\mathrm{2}} \right)}{\left(\mathrm{2}\:{x}^{\mathrm{2}} +\mathrm{9}\right)^{\mathrm{2}} }{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 73484 by abdomathmax last updated on 13/Nov/19 $${decompose}\:{inside}\:{C}\left({x}\right)\:{the}\:{fraction} \\ $$$${F}\left({x}\right)=\frac{\mathrm{1}}{\left({x}^{\mathrm{2}} \:+\mathrm{1}\right)^{{n}} } \\ $$$${calculate}\:\int_{\mathrm{0}} ^{\infty} \:{F}\left({x}\right){dx} \\ $$ Answered by mind is power…
Question Number 73483 by abdomathmax last updated on 13/Nov/19 $${find}\:\int\:\:\:\:\frac{{dx}}{{x}+\mathrm{2}−\sqrt{{x}^{\mathrm{2}} −{x}\:+\mathrm{7}}} \\ $$ Answered by MJS last updated on 13/Nov/19 $$\int\frac{{dx}}{{x}+\mathrm{2}−\sqrt{{x}^{\mathrm{2}} −{x}+\mathrm{7}}}=\int\frac{{dx}}{{x}+\mathrm{2}−\sqrt{\left({x}−\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} +\frac{\mathrm{27}}{\mathrm{4}}}}= \\ $$$$\:\:\:\:\:\left[{t}=\frac{\sqrt{\mathrm{3}}}{\mathrm{9}}\left(\mathrm{2}{x}−\mathrm{1}\right)\:\rightarrow\:{dx}=\frac{\mathrm{3}\sqrt{\mathrm{3}}}{\mathrm{2}}{dt}\right]…
Question Number 73482 by abdomathmax last updated on 13/Nov/19 $${find}\:\int\:\:\:\:\frac{{dx}}{\:\sqrt{{x}^{\mathrm{2}} +\mathrm{1}}+\sqrt{{x}^{\mathrm{2}} \:+\mathrm{3}}} \\ $$ Commented by abdomathmax last updated on 17/Nov/19 $${let}\:{I}\:=\int\:\:\:\frac{{dx}}{\:\sqrt{{x}^{\mathrm{2}} +\mathrm{1}}+\sqrt{{x}^{\mathrm{2}} \:+\mathrm{3}}}\:\Rightarrow \\…
Question Number 73480 by abdomathmax last updated on 13/Nov/19 $${find}\:\int_{\mathrm{0}} ^{\infty} \:\:{xe}^{−{x}^{\mathrm{2}} } \:{arcran}\left({x}+\frac{\mathrm{1}}{{x}}\right){dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 73481 by abdomathmax last updated on 13/Nov/19 $${find}\:\int\:\:{ln}\left({x}−{cosx}\right){dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com