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Category: Integration

Question-62826

Question Number 62826 by Cheyboy last updated on 25/Jun/19 Commented by mathmax by abdo last updated on 25/Jun/19 $$\left.{b}\right)\:{I}\:=\int_{\mathrm{0}} ^{\pi} \:\:\frac{{sin}\theta}{\:\sqrt{\pi−\theta}}\:\:{changement}\sqrt{\pi−\theta}\:={x}\:{give}\:{I}\:=\int_{\sqrt{\pi}} ^{\mathrm{0}} \:\frac{{sin}\left(\pi−{x}^{\mathrm{2}} \right)}{{x}}\:\left(−\mathrm{2}{x}\right){dx} \\…

let-U-n-0-cos-ch-nx-3-x-2-2-dx-1-calculate-U-n-interms-of-n-2-find-lim-n-n-U-n-and-lim-n-n-2-U-n-3-study-the-serie-U-n-

Question Number 62828 by mathmax by abdo last updated on 25/Jun/19 $${let}\:{U}_{{n}} =\int_{\mathrm{0}} ^{+\infty} \:\:\frac{{cos}\left({ch}\left({nx}\right)\right)}{\left(\mathrm{3}+{x}^{\mathrm{2}} \right)^{\mathrm{2}} }{dx} \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:{U}_{{n}} \:{interms}\:{of}\:{n} \\ $$$$\left.\mathrm{2}\right)\:{find}\:{lim}_{{n}\rightarrow+\infty} \:{n}\:{U}_{{n}} \:\:\:\:\:{and}\:{lim}_{{n}\rightarrow+\infty} \:{n}^{\mathrm{2}}…

let-U-n-0-arctan-nt-1-n-2-t-2-dt-with-n-natural-1-1-calculate-U-n-2-calculate-lim-n-n-2-U-n-3-study-the-convergence-of-U-n-

Question Number 62812 by mathmax by abdo last updated on 25/Jun/19 $${let}\:{U}_{{n}} =\int_{\mathrm{0}} ^{+\infty} \:\:\frac{{arctan}\left({nt}\right)}{\mathrm{1}+{n}^{\mathrm{2}} {t}^{\mathrm{2}} }{dt}\:\:\:\:{with}\:{n}\:{natural}\geqslant\mathrm{1} \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:{U}_{{n}} \\ $$$$\left.\mathrm{2}\right)\:{calculate}\:{lim}_{{n}\rightarrow+\infty} \:{n}^{\mathrm{2}} \:{U}_{{n}} \\ $$$$\left.\mathrm{3}\right)\:{study}\:{the}\:{convergence}\:{of}\:\Sigma\:{U}_{{n}}…

1-find-2x-2-1-x-1-x-3-x-2-x-2-dx-2-calculate-5-2x-2-1-x-1-x-3-x-2-x-2-dx-

Question Number 62811 by mathmax by abdo last updated on 25/Jun/19 $$\left.\mathrm{1}\right)\:{find}\:\:\int\:\:\:\frac{\mathrm{2}{x}^{\mathrm{2}} −\mathrm{1}}{\left({x}+\mathrm{1}\right)\left({x}−\mathrm{3}\right)\left({x}^{\mathrm{2}} −{x}+\mathrm{2}\right)}{dx} \\ $$$$\left.\mathrm{2}\right){calculate}\:\int_{\mathrm{5}} ^{+\infty} \:\:\:\:\frac{\mathrm{2}{x}^{\mathrm{2}} −\mathrm{1}}{\left({x}+\mathrm{1}\right)\left({x}−\mathrm{3}\right)\left({x}^{\mathrm{2}} −{x}+\mathrm{2}\right)}{dx} \\ $$ Commented by Prithwish…

Question-128346

Question Number 128346 by Ahmed1hamouda last updated on 06/Jan/21 Answered by MJS_new last updated on 06/Jan/21 $$\int{x}^{\mathrm{2}} \sqrt{\mathrm{4}{x}^{\mathrm{2}} +\mathrm{1}}{dx}= \\ $$$$\:\:\:\:\:\left[{t}=\mathrm{2}{x}+\sqrt{\mathrm{4}{x}^{\mathrm{2}} +\mathrm{1}}\:\rightarrow\:{dx}=\frac{\sqrt{\mathrm{4}{x}^{\mathrm{2}} +\mathrm{1}}}{\mathrm{2}\left(\mathrm{2}{x}+\sqrt{\mathrm{4}{x}^{\mathrm{2}} +\mathrm{1}}\right)}{dt}\right] \\…

f-t-0-e-xt-x-t-2-dx-with-t-0-1-study-the-set-of-definition-for-f-t-2-study-the-continuity-of-f-3-study-the-derivability-of-f-4-developp-f-at-integr-serie-

Question Number 62808 by mathmax by abdo last updated on 25/Jun/19 $${f}\left({t}\right)\:=\int_{\mathrm{0}} ^{+\infty} \:\:\frac{{e}^{−{xt}} }{\left({x}+{t}\right)^{\mathrm{2}} }{dx}\:\:\:\:{with}\:{t}\geqslant\mathrm{0} \\ $$$$\left.\mathrm{1}\right)\:{study}\:{the}\:{set}\:{of}\:{definition}\:{for}\:{f}\left({t}\right) \\ $$$$\left.\mathrm{2}\right){study}\:{the}\:{continuity}\:{of}\:{f} \\ $$$$\left.\mathrm{3}\right){study}\:{the}\:{derivability}\:{of}\:{f} \\ $$$$\left.\mathrm{4}\right)\:{developp}\:{f}\:{at}\:{integr}\:{serie} \\…