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Category: Integration

6-sinx-cosx-sinx-cosx-dx-

Question Number 8281 by tawakalitu last updated on 06/Oct/16 6sinxcosxsinx+cosxdx Answered by Yozzias last updated on 06/Oct/16 sinxsinx+cosx=1cosxsinx+cosxI=sinxcosxsinx+cosxdx=(1cosxsinx+cosx)cosxdx$$=\int\left(\mathrm{cosx}−\frac{\mathrm{cos}^{\mathrm{2}} \mathrm{x}}{\mathrm{sinx}+\mathrm{cosx}}\right)\mathrm{dx}…

cos-x-7-1-3-sin-x-6-dx-

Question Number 139259 by bobhans last updated on 25/Apr/21 cosx+73sinx+6dx=? Answered by Dwaipayan Shikari last updated on 25/Apr/21 cosx+73sinx+6dx=log(sinx+6)+731sinx+6dx$$={log}\left({sinx}+\sqrt{\mathrm{6}}\right)+\mathrm{2}\sqrt[{\mathrm{3}}]{\mathrm{7}}\:\int\frac{\mathrm{1}}{\frac{\mathrm{2}{t}}{\mathrm{1}+{t}^{\mathrm{2}} }+\sqrt{\mathrm{6}}}.\frac{{dt}}{\mathrm{1}+{t}^{\mathrm{2}} }\:\:\:\:\:\:\:\:\:\:\:{tan}\frac{{x}}{\mathrm{2}}={t}…