Category: Integration

Question Number 7898 by tawakalitu last updated on 23/Sep/16 $$\int {cos}^{6}xdx$$ Commented by sandy_suhendra last updated on 24/Sep/16 $${cos}^{6}x={\left({cos}^{2}x\right)}^3$$$$\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\left(\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{2}}{cos}\mathrm{2}{x}\right)^{\mathrm{3}}…

Question Number 138971 by mathmax by abdo last updated on 20/Apr/21 $$\mathrm{calculate}{\int }_0^{\mathrm{\infty }}\frac{\arctan ({\mathrm{x}}^2-1)}{{\mathrm{x}}^2+4}\mathrm{dx}$$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 73428 by Learner-123 last updated on 12/Nov/19 $$Evaluate:$$$$1){\int }_{-2}^2{\int }_{-\sqrt{4-x^2}}^{\sqrt{4-x^2}}(3-x)dydx.$$$$\left(afterchangingtheintegraltopolarform\right).$$$$$$$$\left.\mathrm{2}\right)\:\int_{\mathrm{0}} ^{\mathrm{4}}…

Question Number 7880 by tawakalitu last updated on 22/Sep/16 $$\int \left(\sqrt{1-x-x^2}\right)dx$$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 138940 by mnjuly1970 last updated on 20/Apr/21 $$\dots mathematics..$$$$provethat:$$$$\mathit{\varphi }={\int }_0^{\mathrm{\infty }}\frac{arctan\left(x\right).ln(1+x^2)}{1+x^2}dx$$$$=\frac{{\pi }^{2}ln\left(2\right)}{4}+\frac{7}{8}\zeta \left(3\right)$$ Terms of…