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Category: Integration

6-sinx-cosx-sinx-cosx-dx-

Question Number 8281 by tawakalitu last updated on 06/Oct/16 6sinxcosxsinx+cosxdx Answered by Yozzias last updated on 06/Oct/16 sinxsinx+cosx=1cosxsinx+cosxI=sinxcosxsinx+cosxdx=(1cosxsinx+cosx)cosxdx$$=\int\left(\mathrm{cosx}−\frac{\mathrm{cos}^{\mathrm{2}} \mathrm{x}}{\mathrm{sinx}+\mathrm{cosx}}\right)\mathrm{dx}…