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Category: Integration

Question-73258

Question Number 73258 by Lontum Hans last updated on 09/Nov/19 Answered by MJS last updated on 09/Nov/19 well,justdoitu=1+coshxdx=dusinhx$$…=\underset{\mathrm{2}} {\overset{\mathrm{3}} {\int}}\frac{{du}}{{u}\left({u}−\mathrm{1}\right)}=\left[\mathrm{ln}\:\frac{{u}−\mathrm{1}}{{u}}\right]_{\mathrm{2}} ^{\mathrm{3}}…