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Category: Integration

Question-7397

Question Number 7397 by Tawakalitu. last updated on 26/Aug/16 Answered by sandy_suhendra last updated on 27/Aug/16 sinx=n=0(1)nx2n+1(2n+1)!$$\frac{\mathrm{1}}{{x}}\:{sin}\:{x}\:=\:\frac{\mathrm{1}}{{x}}\:\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}}…