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Category: Integration

nice-calculus-prove-0-1-1-1-ln-2-x-dx-0-sin-x-1-x-dx-

Question Number 136497 by mnjuly1970 last updated on 22/Mar/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:……{nice}\:\:\:\:{calculus}….. \\ $$$$\:\:\:\:{prove}::\:\: \\ $$$$\:\:\:\:\:\:\:\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{\mathrm{1}}{\mathrm{1}+{ln}^{\mathrm{2}} \left({x}\right)}{dx}=\int_{\mathrm{0}\:} ^{\:\infty} \frac{{sin}\left({x}\right)}{\mathrm{1}+{x}}{dx} \\ $$$$ \\ $$ Commented by…

0-7-2-x-1-2x-1-1-3-dx-

Question Number 5422 by love math last updated on 14/May/16 $$\int_{\mathrm{0}} ^{\frac{\mathrm{7}}{\mathrm{2}}} \left({x}+\mathrm{1}\right)\left(\mathrm{2}{x}+\mathrm{1}\right)^{\frac{\mathrm{1}}{\mathrm{3}}} {dx} \\ $$ Answered by nchejane last updated on 14/May/16 $$=\left[\frac{\mathrm{3}}{\mathrm{8}}\left({x}+\mathrm{1}\right)\left(\mathrm{2}{x}+\mathrm{1}\right)^{\frac{\mathrm{4}}{\mathrm{3}}} \right]_{\mathrm{0}}…

1-3-ln-3x-2-dx-

Question Number 5425 by love math last updated on 14/May/16 $$\int_{\mathrm{1}} ^{\mathrm{3}} {ln}\left(\mathrm{3}{x}−\mathrm{2}\right){dx} \\ $$ Answered by nchejane last updated on 14/May/16 $$\left[{xln}\left(\mathrm{3}{x}−\mathrm{2}\right)\right]_{\mathrm{1}} ^{\mathrm{3}} −\mathrm{3}\int_{\mathrm{1}}…

0-50pi-3-sinx-dx-

Question Number 136481 by BHOOPENDRA last updated on 22/Mar/21 $$\int_{\mathrm{0}} ^{\frac{\mathrm{50}\pi}{\mathrm{3}}} \mid{sinx}\mid{dx} \\ $$ Answered by MJS_new last updated on 22/Mar/21 $$\underset{\mathrm{0}} {\overset{\mathrm{50}\pi/\mathrm{3}} {\int}}\mid\mathrm{sin}\:{x}\mid{dx}=\mathrm{33}\underset{\mathrm{0}} {\overset{\pi/\mathrm{2}}…

a-Let-I-0-e-x-x-2-dx-Show-that-it-is-legitimate-to-take-the-derivative-of-I-and-also-I-0-Then-show-that-

Question Number 136476 by Ar Brandon last updated on 22/Mar/21 $$\left(\mathrm{a}\right)\:\mathrm{Let}\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{I}\left(\alpha\right)=\int_{\mathrm{0}} ^{\infty} \mathrm{e}^{−\left(\mathrm{x}−\frac{\alpha}{\mathrm{x}}\right)^{\mathrm{2}} } \mathrm{dx} \\ $$$$\mathrm{Show}\:\mathrm{that}\:\mathrm{it}\:\mathrm{is}\:\mathrm{legitimate}\:\mathrm{to}\:\mathrm{take}\:\mathrm{the}\:\mathrm{derivative}\:\mathrm{of}\:\mathrm{I}\left(\alpha\right)\:\mathrm{and}\:\mathrm{also}\:\mathrm{I}'\left(\alpha\right)= \\ $$$$\mathrm{0}.\:\mathrm{Then}\:\mathrm{show}\:\mathrm{that} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{I}\left(\alpha\right)=\frac{\sqrt{\pi}}{\mathrm{2}}. \\ $$$$\left(\mathrm{b}\right)\:\mathrm{Use}\:\left(\mathrm{a}\right)\:\mathrm{to}\:\mathrm{prove}…