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Category: Integration

cos-2-x-cos-x-1-sin-x-cos-x-dx-

Question Number 129274 by bramlexs22 last updated on 14/Jan/21 cos2x+cosx1+sinx+cosxdx? Answered by liberty last updated on 14/Jan/21 cosx(cosx+1)sinx+2cos2(x2)dx=cosx(2cos2(x2))2cos(x2)[sin(x2)+cos(x2)]dx=$$\:\int\:\frac{\mathrm{cos}\:\left(\frac{\mathrm{x}}{\mathrm{2}}\right)\left(\mathrm{cos}\:\left(\frac{\mathrm{x}}{\mathrm{2}}\right)+\mathrm{sin}\:\left(\frac{\mathrm{x}}{\mathrm{2}}\right)\right)\left(\mathrm{cos}\:\left(\frac{\mathrm{x}}{\mathrm{2}}\right)−\mathrm{sin}\:\left(\frac{\mathrm{x}}{\mathrm{2}}\right)\right)}{\mathrm{sin}\:\left(\frac{\mathrm{x}}{\mathrm{2}}\right)+\mathrm{cos}\:\left(\frac{\mathrm{x}}{\mathrm{2}}\right)}\mathrm{dx}=…