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Category: Integration

Question-135888

Question Number 135888 by mnjuly1970 last updated on 16/Mar/21 Answered by mindispower last updated on 19/Mar/21 recalχ2(x)=li2(x)li2(x)2,chifunction$${we}\:{have}\:\chi_{\mathrm{2}} \left(\frac{\mathrm{1}−{x}}{\mathrm{1}+{x}}\right)+\chi_{\mathrm{2}} \left({x}\right)=\frac{\pi^{\mathrm{2}} }{\mathrm{8}}+\frac{{ln}\left({x}\right){ln}\left(\frac{\mathrm{1}+{x}}{\mathrm{1}−{x}}\right)}{\mathrm{2}}…