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Category: Integration

1-1-cot-x-dx-

Question Number 71814 by Aman Arya last updated on 20/Oct/19 $$\int\frac{\mathrm{1}}{\mathrm{1}+\mathrm{cot}\:{x}}{dx} \\ $$ Commented by mathmax by abdo last updated on 20/Oct/19 $${let}\:{I}=\int\:\frac{{dx}}{\mathrm{1}+{cotanx}}\:\Rightarrow{I}=\int\:\frac{{dx}}{\mathrm{1}+\frac{{cosx}}{{sinx}}}\:=\int\frac{{sinx}}{{sinx}\:+{cosx}}{dx} \\ $$$${changement}\:{tan}\left(\frac{{x}}{\mathrm{2}}\right)={t}\:{give}\:{I}=\int\:\:\frac{\frac{\mathrm{2}{t}}{\mathrm{1}+{t}^{\mathrm{2}}…

0-pi-4-cos-3-2x-cos-x-dx-

Question Number 137345 by liberty last updated on 01/Apr/21 $$\ell\:=\:\int_{\mathrm{0}} ^{\:\pi/\mathrm{4}} \sqrt{\mathrm{cos}\:^{\mathrm{3}} \left(\mathrm{2}{x}\right)}\:\mathrm{cos}\:{x}\:{dx}\:=?\: \\ $$ Answered by MJS_new last updated on 01/Apr/21 $$\int\mathrm{cos}^{\mathrm{3}/\mathrm{2}} \:\mathrm{2}{x}\:\mathrm{cos}\:{x}\:{dx}= \\…

Question-137328

Question Number 137328 by mnjuly1970 last updated on 01/Apr/21 Answered by Dwaipayan Shikari last updated on 01/Apr/21 $$−\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} {tan}^{\mathrm{2}} \left({x}\right){log}\left({sinx}\right){dx}\:\:\:\:\:\: \\ $$$$=\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} {log}\left({sinx}\right)−\int_{\mathrm{0}}…

Need-help-solving-0-x-x-dx-My-current-working-x-x-e-xlnx-e-xlnx-1-xln-x-x-2-ln-x-2-2-x-3-ln-x-3-3-n-0-1-n-x-n-ln-n-x-n-0-x-

Question Number 6246 by FilupSmith last updated on 20/Jun/16 $$\mathrm{Need}\:\mathrm{help}\:\mathrm{solving}\:\int_{\mathrm{0}} ^{\:\infty} {x}^{−{x}} {dx} \\ $$$$\mathrm{My}\:\mathrm{current}\:\mathrm{working}: \\ $$$${x}^{−{x}} ={e}^{−{x}\mathrm{ln}{x}} \\ $$$${e}^{−{x}\mathrm{ln}{x}} =\mathrm{1}−{x}\mathrm{ln}\left({x}\right)+\frac{{x}^{\mathrm{2}} \mathrm{ln}\left({x}\right)^{\mathrm{2}} }{\mathrm{2}!}−\frac{{x}^{\mathrm{3}} \mathrm{ln}\left({x}\right)^{\mathrm{3}} }{\mathrm{3}!}+……