Question Number 133048 by mnjuly1970 last updated on 18/Feb/21 $$\:\:\:\:\:\:\:{nice}\:…..{calculus}… \\ $$$$\:\:\:{evaluate}\:::\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\left(\frac{\mathrm{H}_{{n}} }{{n}^{\mathrm{2}} +{n}}\right)=? \\ $$$$ \\ $$ Terms of Service Privacy Policy…
Question Number 67513 by mhmd last updated on 28/Aug/19 $$\int{x}^{{n}\:} {lnx}/{n}^{{x}} \:{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 133050 by mnjuly1970 last updated on 18/Feb/21 $$\:\:\:\:\:\:\:\:\:\:\:…{nice}\:……{calculus}… \\ $$$$\:\:\:\:\:\boldsymbol{\phi}=\:\int_{\mathrm{0}\:} ^{\:\mathrm{1}} {xli}_{\mathrm{3}} \left({x}\right){dx}=??? \\ $$$$ \\ $$ Answered by Dwaipayan Shikari last updated…
Question Number 133036 by liberty last updated on 18/Feb/21 $$\underset{\mathrm{0}} {\int}^{\:\frac{\pi}{\mathrm{2}}} \:\frac{{dx}}{\mathrm{1}+\mathrm{tan}\:^{\mathrm{2014}} \left({x}\right)}\:=\:\frac{\pi\mathrm{e}^{\mathrm{q}} }{\mathrm{p}} \\ $$$$\mathrm{Find}\:\mathrm{2p}−\mathrm{q}.\: \\ $$ Answered by liberty last updated on 18/Feb/21…
Question Number 133038 by liberty last updated on 18/Feb/21 $$\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\:\frac{{x}^{\mathrm{4}} \left(\mathrm{1}−{x}\right)^{\mathrm{4}} }{\mathrm{1}+{x}^{\mathrm{2}} }\:{dx}\:=? \\ $$ Commented by Dwaipayan Shikari last updated on 18/Feb/21…
Question Number 133027 by Engr_Jidda last updated on 18/Feb/21 $$\overset{\mathrm{2}} {\int}_{\mathrm{0}} {x}^{\mathrm{5}} \left(\mathrm{8}−{x}^{\mathrm{3}} \right)^{\frac{\mathrm{1}}{\mathrm{3}}} {dx} \\ $$ Answered by Olaf last updated on 18/Feb/21 $$\Omega\:=\:\int_{\mathrm{0}}…
Question Number 133016 by metamorfose last updated on 18/Feb/21 $$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \left({tan}\left({x}\right)\right)^{\frac{\mathrm{1}}{{n}}} {dx}\:… \\ $$ Answered by Ar Brandon last updated on 18/Feb/21 $$\mathcal{I}=\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}}…
Question Number 133004 by liberty last updated on 18/Feb/21 $$\mathrm{If}\:\int\:\frac{\mathrm{tan}\:\mathrm{x}}{\mathrm{1}+\mathrm{tan}\:\mathrm{x}+\mathrm{tan}\:^{\mathrm{2}} \mathrm{x}}\:\mathrm{dx}\:=\:\mathrm{x}−\frac{{k}}{\:\sqrt{{A}}}\:\mathrm{tan}^{−\mathrm{1}} \left(\frac{{k}\:\mathrm{tan}\:{x}+\mathrm{1}}{\:\sqrt{{A}}}\right)+\mathrm{C} \\ $$$$\mathrm{where}\:\mathrm{C}\:\mathrm{is}\:\mathrm{constant}\:\mathrm{of}\:\mathrm{integration}. \\ $$$$\mathrm{then}\:\mathrm{the}\:\mathrm{ordered}\:\mathrm{pair}\:\left({k},\mathrm{A}\right)\:\mathrm{is}\: \\ $$$$\mathrm{equal}\:\mathrm{to}\: \\ $$ Answered by EDWIN88 last updated…
Question Number 67467 by ~ À ® @ 237 ~ last updated on 27/Aug/19 $$ \\ $$$$ \\ $$$${Find}\:\:\:\:{f}\left({x}\right)=\int_{\mathrm{0}} ^{\infty} \:\:\frac{\:{tlnt}}{\left(\mathrm{1}+{t}^{\mathrm{2}} \right)^{{x}} }\:{dt}\: \\ $$…
Question Number 67466 by ~ À ® @ 237 ~ last updated on 27/Aug/19 $$ \\ $$$$ \\ $$$${let}\:{consider}\:\:\:{for}\:{all}\:{n}\geqslant\mathrm{1}\:{the}\:{real}\:\left({t}\right)_{{n}} \:={t}\left({t}+\mathrm{1}\right)…..\left({t}+{n}−\mathrm{1}\right) \\ $$$${Find}\:\:\:{L}_{{n}} =\:\int_{\mathrm{0}} ^{\infty} \:\:\frac{\left({t}\right)_{\mathrm{1}}…